No.1703
Ben Smolkin
(U.S.A.)
Warm welcome to Ben!
Original Fairy problems
JF-2022-I:
01.01.2022 - 30.06.2022
No. 1703 Ben Smolkin
U.S.A.
original - 10.04.2022
white Kb2 Pg5
black Pb3b4g6 Ka4 Bf3
h=8.5 2+5
Solution: (click to show/hide)
Interesting problem, but in my opinion,
orthodox h#n (with orthodox pieces and without fairy condition(s)), h=n, h==n, even hs#n, hs=n, hs==n are different parts of the same group : ORTHODOX HELP GENRE
The only explanation I see why h=n is actually considered as fairy is because the mate is the goal in a chess game (with antagonistic play ! )
But it is a little ridiculous when you see the position of an orthodox helpmate, it has very few chances to appear in a chess game.