No.1717
Eric Huber
(Romania)

Original Fairy problems
JF-2022-I:
01.01.2022 - 30.06.2022


Definitions / Определения


No. 1717 Eric Huber
Romania
original - 20.06.2022

black Ke1 Pc2 white Pg2h7d7c7 Kb8
hs#3            b) Ke1->f1            5+2
Anticipés
Anti-Circe (Cheylan)

Solution: (click to show/hide)


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seetharaman kalyan
seetharaman kalyan
June 21, 2022 19:10

Very interesting. But it is a little confusing. I thought Ra1 was pinned by Rh1 and hence no mate (after Kf2 in the first solution)

Last edited 5 months ago by Seetharaman
Nikola Predrag
Nikola Predrag
June 22, 2022 03:24

What is the difference between the pin after 3.Rh1 and the apparently similar pin 4.Rh1-f1 (after 3…Kf2+)?

seetharaman kalyan
seetharaman kalyan
June 22, 2022 19:56
Reply to  Nikola Predrag

deleted

Last edited 5 months ago by Seetharaman
Joost de Heer
Joost de Heer
June 23, 2022 14:28
Reply to  Nikola Predrag

4. Rf1? is not legal because of Rxf1[a8]-c8

Nikola Predrag
Nikola Predrag
June 23, 2022 16:13
Reply to  Joost de Heer

Oh indeed, thanks Joost. So, that’s why the pin by 3.Rh8-e8 isn’t good, since a pin by 4.Re2/f8 would legally parry the check by 3…Kf2.
Still, the rules should mention explicitly the different effects of the standard ‘one-move’ check (as per chess rules) and of the ‘two-legal-moves-in-a-row’ check.