| No.413, 413.1 Linden Lyons (Australia) |
Original Problems, Julia’s Fairies – 2013 (III): September- December →Previous ; →Next ; →List 2013(III) Please send your original fairy problems to: julia@juliasfairies.com |
No.413 by Linden Lyons – Four variants with a single black Grasshopper! (JV)
No.413.1 by Linden Lyons – An improvement to No.413 with author’s gratitude to Seetharaman K.! (JV)
Definitions:
Grasshopper(G): Moves along Q-lines over another unit of either color to the square immediately beyond that unit. A capture may be made on arrival, but the hurdle is not affected.
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No.413 Linden Lyons
Australia
original – 04.11.2013
 =2 (9 + 2)
Grasshoppers: a3, d8, h7, b5 Solution: (click to show/hide)
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No.413.1 Linden Lyons
Australia
Version of No.413 – 10.11.2013
 =2 (11+3)
Grasshoppers: с5, d5, e8, h6 Solution: (click to show/hide)
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A very economical setting of three grasshopper-specific stalemates. Lovely.
Very nice setting. I think it should be possible to make the fourth variation also thematic. If e2 is not guarded twice One possibility (with WPa5) is 2.Ga3-a6 =
What a refreshing idea! Nicely done!
Well done Linden! You have managed to add a nice key and extra variation too !