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No.965 |
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No.965 by Michael Grushko – Fairy promotions in PG problem. (JV)
No.965.1 by Michael Grushko – An improved version to No.965. (JV)
No.965.2 by Michael Grushko – One more improvement to No.965 (a shorter version) after comment by Nikola Predrag. (JV)
Definition:
Grasshopper(G): Moves along Q-lines over another unit of either color to the square immediately beyond that unit. A capture may be made on arrival, but the hurdle is not affected.
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No.965 Michael Grushko |
Solution: (click to show/hide) |
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white Bf1c1 Ke1 Qd1 Ph2g2f2e2d2c2b2a2 Sg1b1 Rh1a1
black Bf8c8 Ke8 Qd8 Ph7g7f7e7d7c7b7a7 Sg8b8 Rh8a8
PG 19.5 (12+13) C- |
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No.965.1 Michael Grushko |
Solution: (click to show/hide) |
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white Bf1c1 Ke1 Qd1 Ph2g2f2e2d2c2b2a2 Sg1b1 Rh1a1
black Bf8c8 Ke8 Qd8 Ph7g7f7e7d7c7b7a7 Sg8b8 Rh8a8
PG 19 (12+13) C- |
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No.965.2 Michael Grushko |
Solution: (click to show/hide) |
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white Bf1c1 Ke1 Qd1 Ph2g2f2e2d2c2b2a2 Sg1b1 Rh1a1
black Bf8c8 Ke8 Qd8 Ph7g7f7e7d7c7b7a7 Sg8b8 Rh8a8
PG 16 (11+14) C- |
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Georgy Evseev’s comment reposted here:
“Cook 1.Sf3 e5 2.Sxe5 d5 3.h4 g5 4.hxg5 d4 5.Rh6 d3 6.e4 dxc2 7.d4 c5 8.Be2 c4 9.Kd2 c3+ 10.Kd3 Qf6 11.Bd2 c1=S+ 12.Kc4 Sb3 13.Qxb3 Qxf2 14.Qb6 cxb2 15.Bb4 Qf6 16.Sd3 Qd8 17.Rf6 bxa1=G 18.g6 Ge5 19.Sb2 Gg7 20.e5”
Cooked, unfortunately, but the main idea seems quite original: Schnoebelen promotion to Grasshopper (the promoted piece on c1 is captured without making a move after the promotion). The normal promotions do not work – the white King makes sure to exclude each one of them, by playing Ke1-d2-d3.
The second Ceriani/Frolkin promotion to Grasshopper (16…f1=G) is also nice. Black has only one move to get rid of the promoted piece, and only a Grasshopper can do the job. I hope the problem can be saved.
I think the author’s intention was probably to show the difficult theme Dupont (promotion Ceriani-Frolkin + promotion Pronkin + promotion Schnoebelen) with Grasshoppers.
Good point, Vlaicu. Not having a home square for the Grasshopper, the initial square of any pawn (which is the procreator of any fairy piece) counts as the Grasshopper’s home square. So, according to this definition, the Gg7 is a Pronkin piece.
The initial square of any “captured” pawn. As bPg7 is the only captured pawn which was not promoted, g7 is the only available Pronkin square for a black Grasshopper!
Yes, this is the “theme Dupont”, where moreover the Ceriani-Frolkin piece is a Prentos one (captured by an officer).
I wish a full success to Michael in making correct this very good idea.
Nicolas, the distinction that you make is correct, but I don’t agree with the conclusion. The Pg7 is not the only black pawn that has been captured. The same happened to Pd7 and Pe7 (both were captured after promotion).
The question is whether a bGc7 would be a Pronkin piece or not. The Pc7 is missing. In orthodox proof games, we assume that a missing piece was captured (how else would it disappear?). In this case, however, the pawn can disappear through promotion. It seems to me that even a bGc7 would count as a Pronkin piece, since the original pawn is nowhere to be found. A kind of “pawn circuit Pronkin”, if you prefer.
What is clear is that, to be a Pronkin, a fairy piece must visit the initial square of a captured pawn. We disagree on the exact meaning of “captured pawn”. For you it fills the definition even when the pawn is promoted and then captured. For me a pawn which is promoted is no more a pawn, and therefore can’t be captured (only its “new personality” can). But maybe I’m wrong here, is there some official rule which governs such a thing?
The pawn and the Grasshopper that comes from it have to count as the same piece, otherwise we would not have a Pronkin, in the first place. According to this reasoning, the capture at any stage (before, or after promotion) should not be separated. In any case, it is not important, as we both agree that in this problem, the Pronkin theme is indisputable, regardless of the interpretation.
bG7 is exactly the opposite to the idea of a Pronkin piece.
bG on the diagram has OBVIOUSLY been moved.
Pronkin piece on a diagram APPEARS as “OBVIOUSLY NOT MOVED”.
In such a case the fairy piece must appear in the initial game array – not only as a promoted piece. This is indeed possible, for example if we begin the game with 2 grasshoppers instead of the 2 queens.
Such a kind of fairy proof game already exists – for example the Messigny 2010 3-4 prize from Le Gleuher and I – with kangourous instead of queens.
Nikola, this is what we get sometimes, when we try to apply orthodox themes in the fairy world. Your objection makes perfect sense. Even if we accept the bGg7 as a Pronkin piece, what value does it have?
Furthermore, according to some fairy conditions, the initial squares of fairy pieces are on the 8th rank (for white) – the circe rebirth square of a Grasshopper is the 8th rank of the file on which it was captured. Whatever we define as the initial square of a fairy piece, it would inevitably be ambiguous and unreliable.
At least, the other two thematic elements of this PG (Schnoebelen and Ceriani/Frolkin) are nice and clear.
If a promoted piece appears to a solver as a piece that has never left its home square, that’s essentially Pronkin.
This essence is not changed if a fairy piece appears in the initial game array.
The hybrid of the orthodox initial game array and a fairy piece on the diagram might result with a hybrid of Anti-Pronkin&Pronkin logic.
Just as an example, in Michael’s PG, after 16.Be2 Ga1xc1!, the position could be considered as PG 16.0.
Gc1 would appear to a solver as standing on the square of its first appearance in the game, which might be (conditionally) treated as its initial square.
The solving would reveal that it’s actually the 2nd bG which came from its (conditionally) initial square a1, but also that there was indeed the 1st bGc1 in the previous course of the game.
Adding a spare move Qd1-b3-f3 is not a very safe correction!
1.h4 g5 2.hxg5 c5 3.Rh6 c4 4.Rf6 c3 5.g6 cxb2 6.c5 bxa1=G 7.Sf3 Gg7 8.d5 e5 9.Kd2 e4 10.Kc3 e3 11.Se5 exf2 12.e3 d5 13.Qf3 dxc4 14.Be2 f1=G 15.Kxc4 Gd3 16.Sxd3 ? 17.Ba3 ? 18.Bb4 ? 19.Sb2 ?