# No.242,243 (PH)

 No.242, 243 Peter Harris (South Africa) Original Problems, Julia’s Fairies – 2013 (I): January – April →Previous ; →Next ; →List 2013(I) Please send your original fairy problems to: julia@juliasfairies.com

Two problems by Peter Harris demonstrating Haaner Chess

No.242 – ser-h=3 by Peter Harris – Very active play of the black King!

No.243 – ser-hs#6 by Peter Harris – A problem of just 3 pieces! For solvers: the stipulation means a series of 5 black moves, and then 1 white and 1 black half-move!

(JV)

Definitions:

Haanеr Chess : Any square left can’t be neither occupied nor crossed.

Super-Circe – When captured, a piece is reborn on any free field on the chess board without causing self-check or selfmate. Possible is also removal of captured piece from the board. The Pawns (white, black, neutrals, half- neutrals) can be reborn on the first or eight row also. When reborn on the first row  (for Black) or on the eight row (for White) the promotion is obligatory. When reborn on the first row  (for White) or on the eight row (for Black) the Pawns are immovable.

Chameleon Chess: All pieces on the board which are displayed as orthodox  Q, R, B, S,  are Chameleons. A Pawn can promote only in Chameleon-pieces.

Chameleon: On completing a move, a Chameleon (from classical standard type) changes into another piece, in the sequence Q-S-B-R-Q…  Promotion may be to a chameleon at any stage in the cycle.

 No.242 Peter Harris South Africa original-28.01.2013   ser-h=3         b) Pd5→f2            (1+3)Haaner ChessSuper-Circe     Solution: (click to show/hide)   a) 1.Kd8-d7 2.Kd7*e7 [+wPe8=wB] 3.Ke7*e8 [+wBh1] Bh1*d5 [+bPf8] = b) 1.Kd8*e7 [+wPd7] 2.Ke7*d7 [+wPe8=wR] 3.Kd7*e8 [+wRg2] Rg2*f2 [+bPh1=bB] = No.243 Peter Harris South Africa original-28.01.2013   ser-hs#6       b) Kh8→g8           (2+1)Haaner ChessSuper-CirceChameleon Chess     Solution: (click to show/hide)   a) 1.b2-b1=S 2.Sb1-a3=B 3.Ba3-e7=R 4.Re7*f7=Q [+wPh6] 5.Qf7-g8=S h6-h7 6.Sg8-f6=B # b) 1.b2-b1=B 2.Bb1-c2=R 3.Rc2-f2=Q 4.Qf2*f7=S [+wPg7] 5.Sf7-h8=B Kg8*h8 [+bBg1] 6.Bg1-h2=R #