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No.1362 |
Original Fairy problems |
Definition: (click to show/hide)
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No.1362 Manfred Rittirsch |
Solution: (click to show/hide) |
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white Ke4 Rb3b7
black Kc5 Qc8 Rd2g1 Bf4g2 Sa4f8 Pf6
h#2 2 solutions (3+9) |
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No.1362 |
Original Fairy problems |
Definition: (click to show/hide)
|
No.1362 Manfred Rittirsch |
Solution: (click to show/hide) |
|
white Ke4 Rb3b7
black Kc5 Qc8 Rd2g1 Bf4g2 Sa4f8 Pf6
h#2 2 solutions (3+9) |
|
Merry X-Mas and a happy New Year! (Author)
The cyclic change of functions between two black and two white pieces is more apparent if you write it like this –
bRd2 (I) Block of rebirth (II) Block of flight
bBf4 (I) Block of flight (II) Closing of Rg1-a1
wRb3 (I) Closing of Rg1-a1 (II) Mate
wRb7 (I) Mate (II) Block of rebirth
Right – thank you, Kjell! I will keep an eye on explicity in my article to come. Just sent an improved table to Julia.
Replaced the table in the comments!
[img]https://pixabay.com/de/daumen-hoch-blaue-daumen-hand-2859340/[/img]
Image hasn’t got linked. Manfred gives a blue thumbs up!