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Original Problems (page 109)Original fairy problems published during 2012 will participate in the informal tourney JF-2012. The site is mostly about fairies, but h# and s# are also welcomed for publication! Please send your problems to my e-mail: julia@juliasfairies.com Go to →List of Problems; →Page 108 ; →Page 110 |
What’s a nice surprise – Peter Harris is on the site again! The last problem by Peter I’ve published was on 18-Aug, and the total number of his problems on Julia’sFairies was 19. So, welcome to the 20th problem by Peter!
No.174 – hs=5 by Peter Harris – Total modification of the initial position, typical for Sentinels condition. (JV)
Definitions:
Anti-Andernach Chess: a unit (not King) changes color after its moves unless that move is a capture. (Or: a unit (King excluded) changes color on completion of a non-capturing move.)
Sentinels Pion advers: When a piece (not a Pawn) moves, a Pawn of the colour of the opposite side appears on the vacated square if it is not on the first or the last rank, and if there are less than 8 Pawns of that colour on the board.
Maximummer – Black must play the geometrically longest move or may choose from among longest moves of equal length, distances being measured from the center of each square. Diagonal and oblique distances are measured from the orthogonal coordinates by using Pythagora’s theorem (take the square root of the sum of the squares of the orthogonal distances). All other orthodox chess rules apply.
Black Maximummer ultra: Black’s only legal move is his longest – calculated as per Maximummer rules.
White Maximummer ultra: White’s only legal move is his longest – calculated as per Maximummer rules.
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No.174 Peter Harris
South Africa
original-24.11.2012
 hs=5 (2+1)
Black Maximummer ultra White Maximummer ultra Sentinelles Pion Advers Anti-Andernach Solutions: (click to show/hide)
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The diagrams are made on WinChloe and its Echecs font is used for Logo design
I’d like to comment that author suggests to solvers to look at his educational example published here to the problem No.59.