No.277, 278 
Chris Feather (England)

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Original Problems, Julia’s Fairies – 2013 (I): January – April

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Please send your original fairy problems to: julia@juliasfairies.com


No.277, 278 – Two very exotic problems by Chris Feather! Enjoy a combination of fairy conditions Anti-Kings+Anti-Circe and author’s explanations to the problems! I’m also grateful to Chris for the definitions he’s sent with his problems! (JV)


Definitions:

Anti-Kings: A king is in check if he is not attacked. Mate occurs when a  king is not attacked and his side has no move which exposes him to attack. (Of course kings may not be captured.)

Anti-Circe: After a capture the capturing piece (Ks included) must immediately be removed to its game array square (necessarily vacant, else the capture is illegal). R, B & S go to the square of the same colour as the capture; Ps stay on the file of capture.


No.277 Chris Feather
England
original-05.03.2013
 
277-h#2-cf
h#2              3 solutions        (2+1+2n)
Anti-Kings+Anti-Circe
 
 
Solutions: (click to show/hide)
 
No.278 Chris Feather
England
original-05.03.2013
 
278-h#2-cf
h#2              2 solutions        (3+1+1n)
Anti-Kings+Anti-Circe
 
 
Solutions: (click to show/hide)
 

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Geoff Foster
Geoff Foster
7 years ago

What a terrific idea! Another interesting possibility is:

h#2 (b)bKg8>e4
white kg1
black kg8
neutral pf7 ph2

(a) 1.nPh1=nR nPf8=nR+ 2.nRh8+ Kh1#

Now Black cannot play 3.Kh7??, because the nRh8 doesn’t attack the bKh7, because the nR’s rebirth square (h1) is occupied. For the same reason the bK cannot play 3.Kxf8?? or 3.Kxh8??, because it would be reborn on e8, which is a white-coloured square.

(b) 1.nPh1=nQ nPf8=nB 2.nBb4 Kxh1[wKe1]#

seetharaman
seetharaman
7 years ago

Anti-king is a very interesting condition. Chris has shown two excellent ideas in combination with Anti-Circe ! Thanks Chris.