Julia's Fairies

No.354 (PAP)

Petko A. Petkov (Bulgaria)


Original Problems, Julia’s Fairies – 2013 (II): May – August

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No.354 – Petko A. Petkov – Wonderful Disparate problem! Enjoy author’s detailed comments to all 3 solutions! I’m so grateful for the dedication! (JV)


Camel – (1,3) Leaper

Zebre – (2,3) Leaper

Disparate: If one side makes a move with a piece of type “x” (black, white, neutral, half-neutral, etc., King included), the other side cannot answer immediately by moving a piece of the same type “x”. (For example: white Qc1, black Ka8,Qa7 – mate in 1 move. After 1.Qc8#, Black is mated because 1…Qb8? is illegal. The mate is possible also with the neutral nQc1 – after 1.nQc8#. Black cannot move the same neutral Queen.) Every Pawn’s promotion is a Pawn’s move, therefore after such promotion (into any possible piece) the other side cannot answer immediately with its Pawn. We can say that after the move of the figure of type “x” any enemy figure of type “x” falls under Half-moving paralysis. This paralysis disappears immediately on the next half-move, if the opponent plays with another piece of type “y”.
This is the main version of Disparate (the programmer is Stephen Emmerson), that is presented only in Popeye (starting 4,53 version), and answers to the definition of the inventor Romeo Bedoni (2004) and to the requirements about this condition of the editors of “Phenix”. Using Popeye‘s version of Disparate in 2010 was organized a big international tournament Bedoni – 80 Jubilee, with results published in the magazine “Phenix” – No.191-192/2010. In the same number was also published a big article by Petko A.Petkov about Disparate, dedicated to its inventor Romeo Bedoni.  Important noteDisparate condition is not included in Popeye‘s manual, but it is implemented there and can be used as “Disparate“.
Another version of Disparate you can find in WinChloe, but it is based on the different rules.  

No.354 Petko A. Petkov
Dedicated to Julia Vysotska!
                               hs=3                                   (1+7+7)      (С+ Popeye 4.63)
b) Pb4→b6
c) Pe3→c6
Camels: c1, g7 
Zebras: f1, f8
Solutions: (click to show/hide)

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