Peter Harris (South Africa)


Original Problems, Julia’s Fairies – 2016 (I): January – June

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No.1063 Peter Harris
South Africa

original – 06.05.2016

Solutions: (click to show/hide)

white ke6 qa8 ra4 bh7 sg5 black ke4 qh3 re8 bf7 sc7

hs#3               duplex               (5+5)
Chameleon Chess
Andernach Chess

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Nikola Predrag
Nikola Predrag
May 6, 2016 21:06

This is fantastic! And a brief analysis shows that all pieces make the mechanism, I hope it’s true.

A few facts:
In the first mate, 4.wBf3-g4?? would be a selfcheck by bRe8 anyway. wQs & bBf7 could be removed from the mate.

In duplex, 1.Qe3=bS? Kf6 fails for the lack of tempo in W2. Just for the curiosity, I added wPa3 (for tempo) and there were cooks. Then I tried adding wP to any square and the various cooks have illustrated how delicate is the balance of the construction.
Just try it.

Beautiful and highly educative, thanks Peter!

peter harris
peter harris
May 6, 2016 22:07

In the diagram position any non-King moves gives check.

If the AntiAndernach condition also applied, a check could be parried by moving a piece that would change its colour and type to REPLACE the piece giving rise to the check! This parrying move would itself give check! So there can be a sequence of checks. Each move in the sequence would simultaneously parry and check – which is fascinating.

I wrote an article on this idea that appeared in feenschach f-194 July-August 2012 – titled Constellation.

The article featured the following original problem of mine, Con/8, Dedicated to John Rice:

beg pie
whi kc7 qe4 rd7 bg5 sd5
bla ke7 qd8 rb7 bb6 sb5
stip hs#4 opt whi
cond ander antia
chameleonch isa
twi mov e4 d6

(a) 1…Bb6-d4=wR + 2.Sd5-b6=bB + Qd8-g8=wS + 3.Rd4-d6=bQ Rb7-b8=wQ + 4.Bg5-c1=bR + Ke7*d7 #
(b) 1…Bb6-a5=wR + 2.Sd5-b6=bB + Qd8-c8=wS + 3.Ra5-a7=bQ Bb6-e3=wR + 4.Sc8-b6=bB + Ke7-d8 #

Of the 14 half-moves 12 are parry/checks.

It would be a miracle if a problem was made with all moves checks.

Luce Sebastien
Luce Sebastien
May 7, 2016 00:11

Dear Peter,
it is a Great Problem !
I was not familiar with this combination of conditions but
I took a lot of pleasure to understand it.
The begining position is incredible with the two Kings seemingly in check, but in fact no !
And the two solutions are also fantastic, like a miracle !

I am so sorry to add also it is …C+ Winchloe ! 🙂

Nikola Predrag
Nikola Predrag
May 7, 2016 03:01

A lonely King may be not-in-check only if all four (or none) opponent’s officers observe him, since the complete cycle of Chameleon color-changing transformations is needed for the full check-preventing effect of Isardam.

The question is how the pieces of the initial static W&B (artificial) setups will play.
It’s great in No.1063 that only wQa8 doesn’t move, which suggests that duplex offers a way to avoid “immobility” of too much pieces.

May 7, 2016 10:23

Very interesting and beautiful problem!

Ganapathi wrote to me a mail with the following comment (which I am quoting).

“Only after the comments appeared, I understood that neither Kings at start was in check! Then going through the solutions ( it was such a great effort) my head got into a spin literally.
As if this is not enough, he is quoting an earlier problem of his using Antiandernach.
Is Peter a composer or a wizard?!”

Nikola Predrag
Nikola Predrag
May 7, 2016 16:48

Hm, the combination Andernach+Antiandernach is actually simpler than only one of these conditions.
Pieces always change color after moving (capturing or not).

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