Definition: (click to show/hide)
Circe Equipollents: After a piece is captured, it is immediately replaced on the square which is the same distance and direction from the square of its capture, as was that square from the square upon which its captor commenced its move. (If Qf7 captures a Pawn on e7, it is reborn on d7, because d7 is a same distance and direction from e7 as e7 is from f7. Similarly, if Qg7 captures a piece on ‘e7’ its rebirth square is ‘c7’). If the rebirth square is occupied the captured piece disappears. Castling with replaced Rook is permitted. Pawns may be reborn on the 1st and 8th ranks. Pawns reborn on the 8th rank are promoted as part of rebirth and the promotion is chosen by the player who makes the capture, i.e., if White captures a black Pawn, and the black Pawn is reborn on the 8th rank, White (not Black) decides what Black’s Pawn will be promoted to. Pawns reborn on the 1st or 8th rank can make only one-square move (for example black Pc8 can play only on c7 or it can capture an enemy units on ‘b7’ or ‘d7’). During the en passant capture, the Pawn is replaced on the rank opposite of the captor. For example, if Black moves c7-c5, White Pawn on ‘b5’ captures en passant, moves to ‘c6’, while the black Pawn is reborn on ‘d6’.
No.1130 Pierre Tritten France original – 22.09.2016
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Solutions: (click to show/hide)
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White Kf1 Bc5 Sc4 Pd3
Black Kf3 Qb5 Sd5 Sg4 Pd6 Pe3
ser-h#4 2 solutions (4+6) Circe Equipollents
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1.Qb5-a6 2.Qa6*c4[+wSe2] 3.Qc4-c2 4.Qc2*c5[+wBc8] Bc8*g4 #
1.Qb5-a5 2.Qa5*c5[+wBe5] 3.Qc5-c6 4.Qc6*c4[+wSc2] Sc2-e1 # {
(C+ by Popeye 4.75)}
Doubled Chris Feather’s mechanism ‘reculer pour mieux sauter’. (Author)
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A convincing mechanism.
Only the mating move of the 1st solution still needs the condition. the one of the 2nd is orthodox. Shouldn’t there be a hint that there are two solutions?
Oh, sorry, “2 solutions” added under the diagram. Thank you, Hubert!
A pleasant problem !
Thank you Pierre…and Chris !
What is meant by “Feather’s mechanism” here?
It could mean ‘take a step back for a better jump’!
I’ve understood that but where’s a Feather’s mechanism?
There is no ‘Feather mecanism’ but a mechanism used by Chris on F45-4
Oh, thanks for the clarifying reference Pierre. I didn’t know about F45-4.
However, I did know about ‘reculer pour mieux sauter’. I had the idea of a “retreat for a runup for the jump” or “pulling a bowstring”, for http://www.yacpdb.org/#329804
That was a lovely problem Nikola, combining so many themes!
Delicious problem, thanks for showing it, Nikola
very satisfying problem, Nikola
Unfortunately Nikola’s problem is anticipated:
Vyacheslav Vladimirov & Nikolai Ivanovsky
Shakhmaty (Riga)/Sahs 1972
White Ka8 Qc7 Pg6 Ph5 Pf4
Black Kf6 Qb6 Rg8 Rh8 Bh1 Sd8 Sc6
1.Sb8+ Qb7 2.Sdc6 Qf7#
1.Sb7+ Qb8 2.Scd8 Qe5#
Thanks Seetharaman, Andrew and Pierre, I made it in year 2000 and published it almost 5 years later, I can’t remember why such a delay.
However, I didn’t want to show it as “my problem”, but to show the different aspects of a content, of a theme and of a pattern.
It would be interesting to analyze and discuss it.
Pierre has created a complex thematic pattern by using a simple play.
I have created a complex play to achieve an illusion of a simple pattern.
And thanks Geoff!
Obviously, it’s proper to talk about the problem by Vladimirov & Ivanovsky. I’ve seen some partial anticipations of the line-play, but nothing close to such a complete precedent.
🙁
🙁