No.1175 |
Original Problems, Julia’s Fairies – 2016 (II): July – December →Previous ; →Next ; →List 2016(II) Please send your original fairy problems to: julia@juliasfairies.com |
Definitions: (click to show/hide)
Maximummer: Black must play the geometrically longest move or may choose from among longest moves of equal length, distances being measured from the center of each square. Diagonal and oblique distances are measured from the orthogonal coordinates by using Pythagora’s theorem (take the square root of the sum of the squares of the orthogonal distances). All other orthodox chess rules apply.
White Maximummer: Only White must play the geometrically longest moves, Black plays orthodoxal.
Anti-Circe: After a capture the capturing piece (Ks included) must immediately be removed to its game array square (necessarily vacant, else the capture is illegal). Captures on the rebirth square are allowed. Game array squares are determined as in Circe: R, B & S go to the square of the same colour as the capture; Ps stay on the file of capture; fairy pieces go to the promotion square of the file of capture.
Sentinels: When a piece (Ks included but not pawns) moves, a pawn of the same colour appears on the vacated square unless that square is on the first or eighth ranks or there are 8 pawns of that colour on the board already.
No.1175 Arnold Beine |
Solutions: (click to show/hide) |
white Kc6
black Kd1
h008.5 2 solutions (1+1) |
1...Kc6-d5[+wPc6] 2.Kd1-c2 Kd5-e4[+wPd5] 3.Kc2-b3[+bPc2] Ke4-d3[+wPe4] {
} 4.Kb3-a4[+bPb3] Kd3-c4[+wPd3] 5.b3-b2 c6-c7 6.c2-c1=S Kc4-c3[+wPc4] {
} 7.Sc1-a2 + Kc3*b2[wKb2->e1][+wPc3] 8.Sa2*c3[bSc3->b8][+bPa2] c7*b8=R[wRb8->a1] {
} 9.Ka4-b3[+bPa4] {0-0-0
}
1...Kc6-b7[+wPc6] 2.Kd1-e2 Kb7-c8[+wPb7] 3.Ke2-f3[+bPe2] Kc8-d7 {
} 4.Kf3-g4[+bPf3] Kd7-e6[+wPd7] 5.Kg4-h5[+bPg4] Ke6-f5[+wPe6] 6.e2-e1=R e6-e7 {
} 7.Re1*e7[bRe7->h8] Kf5*g4[wKg4->e1][+wPf5] 8.Rh8-a8 b7*a8=R[wRa8->h1] + {
} 9.Kh5-g4[+bPh5] {0-0
(C+ by Popeye 4.75)}
When I saw this problem for the first time I thought that it is a wonderful idea, but after the second sight I wondered why the author used Circe. In my eyes Circe here is a triple weakness: 1. there is no need, because Anticirce is enough to get castling right for White, 2. it produces some more unnecessary Sentinelles-pawns and 3. the b)-solution works also without Circe, here Circe is just a cookstopper. Therefore I tried to find a better presentation of this idea. To gain this I had to change everything: the position, the stipulation, the solution, and of course the fairy conditions, i.e. no Circe. I think my problem is original enough. Although the solution is a halfmove longer, there are much less Sentinelles-Pawns in the final positions, the motivation for the black promotion is harmonious now, no Circe and I could even drop the twinning. I asked Andreas, whether he would prefer being co-author or only mentioned as "after Andreas Thoma". He meant that "after" would be enough. (Author) |
Author’s comment is just added to the problem.