Definitions: (click to show/hide)
Back-to-Back: When a capture is made, the captured unit (except a King) is replaced on the square the capturing unit just leaves. A Pawn is immovable on its 1st rank.
Chameleon Chess: All pieces on the board, which are displayed as orthodox Q, R, B, S, are Chameleons. A Pawn can promote only in Chameleon-pieces.
Reverse Pawn(PP): Moves as Pawn, but in reversal direction.
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No.1178 Karol Mlynka
Slovakia
original – 30.12.2016
Dedicated to Ján Golha 60*
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Solutions: (click to show/hide)
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white PPa2h2
black PPb2e4
hs=4 2 solutions (2+2)
Back-to-Back
Chameleon Chess
Reverse Pawn a2,h2,b2,e4
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1.PPa2-a1=B PPb2-b3 2.Ba1-e5=R PPe4-e1 3.Re5-e2=Q PPe1-h1 4.Qe2-b5=S PPb3-b4 {=}
1.PPh2-h1=B PPe4-e5 2.Bh1-c6=R PPb2-b4 3.Rc6-e6=Q PPe5-a1 4.Qe6-b6=S PPb4-b5 {=
(C+ by Popeye 4.75)}
Chameleon echo model stalemates in Reverse-Pawn-Wenigsteiner without Kings by Back To Back. (Author)
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No.1178 
Karol, thank you for dedication
This problem brings into light an interesting question about equivalence of various fairy elements and their combinations. Totally same content can be shown using the following position:
White Pa7 Ph7
Black Pb7 Pe5
Face-to-Face + Chameleon Chess
hs=4
2.1.1…
C+ by Popeye 4.75
1.a7-a8=B b7-b6 2.Ba8-e4=R e5-e8 3.Re4-e7=Q e8-h8 4.Qe7-b4=S b6-b5 =
1.h7-h8=B e5-e4 2.Bh8-c3=R b7-b5 3.Rc3-e3=Q e4-a8 4.Qe3-b3=S b5-b4 =
Obviously, this version saves one fairy element (no fairy pieces on the board), thanks to reflecting pawn position on the board and choosing other suitable -t- condition. Is there any reason to prefer one of the choices of fairy elements, especially BtB in this case?