kmlynkaNo.1178 
Karol Mlynka
(Slovakia)

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Original Problems, Julia’s Fairies – 2016 (II): July – December

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Definitions: (click to show/hide)


No.1178 Karol Mlynka
Slovakia

original – 30.12.2016
Dedicated to Ján Golha 60*

Solutions: (click to show/hide)

white PPa2h2 black PPb2e4

hs=4            2 solutions             (2+2)
Back-to-Back
Chameleon Chess
Reverse Pawn a2,h2,b2,e4


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Jan Golha
Jan Golha
December 30, 2016 20:34

Karol, thank you for dedication

Juraj Lörinc
Juraj Lörinc
December 30, 2016 23:36

This problem brings into light an interesting question about equivalence of various fairy elements and their combinations. Totally same content can be shown using the following position:

White Pa7 Ph7
Black Pb7 Pe5
Face-to-Face + Chameleon Chess
hs=4
2.1.1…
C+ by Popeye 4.75

1.a7-a8=B b7-b6 2.Ba8-e4=R e5-e8 3.Re4-e7=Q e8-h8 4.Qe7-b4=S b6-b5 =
1.h7-h8=B e5-e4 2.Bh8-c3=R b7-b5 3.Rc3-e3=Q e4-a8 4.Qe3-b3=S b5-b4 =

Obviously, this version saves one fairy element (no fairy pieces on the board), thanks to reflecting pawn position on the board and choosing other suitable -t- condition. Is there any reason to prefer one of the choices of fairy elements, especially BtB in this case?