Michel Caillaud & Jean-Marc Loustau

Original Fairy problems
October’2017 – March’2018

Definitions: (click to show/hide)

No.1262 Michel Caillaud &
Jean-Marc Loustau


original – 22.12.2017

Solution: (click to show/hide)

white Kf2 Qf3 Sa3 Bb2 Rf4 BHa1h6 RHe8f1 Pc2c6g5 black Kd2 Sa5 Bh4 Gc1d1 RHb7d6e3g3 BHb1e1 Pg6

#2                                             (12+12)
Grasshoppers c1,d1
Rookhoppers e8,f1,b7,d6,e3,g3 Bishophoppers a1,h6,b1,e1
a) Anticircé Calvet
b) Anticircé Cheylan

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December 23, 2017 20:41

Superb !

Kjell Widlert
Kjell Widlert
December 25, 2017 01:05

I love subtle twinning, and this is more subtle than most: not a change from one fairy condition to another, but a change between two forms of the same fairy condition! So the changed play (Lacný) is caused solely by the right for a piece to capture on its own rebirth square: legal or not?

The mechanism depends on the fact that b1-c1-d1-e1 are rebirth squares both for white attackers and for black defenders (because they are all fairy pieces). So part b (Cheylan) is fairly automatic: Black leaves a thematic square, so White is able to go there (no capture) but Black is unable to defend by going back (with capture). Part a (Calvet), however, has required constructional tricks: the defences must let in other thematic mates according to the Lacný pattern. This has succeeded very well.

A valuable extra feature is the fact that the two parts have different keys. Naturally, this differentiation is also caused by the difference between Calvet and Cheylan.

Kjell Widlert
Kjell Widlert
December 25, 2017 01:06

(If you read between the lines, you can see that I too find the problem excellent!)

Jacques Rotenberg
Jacques Rotenberg
December 27, 2017 06:22

a) better than b) but it does not really matter here .
Can be shown in a less conventional way:
2# anticirce
the solution being split in two
– if you mean “Cheylan”
– if you mean “Calvet”

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