Sergey Shumeiko (Russia)

Original Fairy problems
October’2017 – March’2018

Definition: (click to show/hide)

No.1280 Sergey Shumeiko

original – 25.02.2018

Solutions: (click to show/hide)

white Bf1c1 Ke1 Qd1 Ph2g2f2e2d2c2b2a2 Sg1b1 Rh1a1 black Bf8c8 Ke8 Qd8 Ph7g7f7e7d7c7b7a7 Sg8b8 Rh8a8

h#2.5                                      (16+16)
b) Pf7→f5 ; c) Sb1→c6 ; d) -Pe7
Duelist Chess

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Luce Sebastien
Luce Sebastien
February 25, 2018 22:36

Very funny! I would like my opponents play like that in classical games of chess ! Congratulations Sergey ! 🙂

Geoff Foster
Geoff Foster
February 25, 2018 22:53

For position b) the only possible proof games are 1.Sa3/Sc3/Sf3/Sh3 f6 2.Sb1/Sg1 f5, so the solution must start with a wS move followed by bPf5-f4.

February 25, 2018 23:23
Reply to  Geoff Foster

Thank You

Luce Sebastien
Luce Sebastien
February 25, 2018 23:11

Sergey, you can add (at the minimum)
e) Rh1->f3
1…e4 2.e5 Bc4 3.Se7 Bxf7‡
the “famous square” f7!!
I take a lot of fun to search other twins.
Thank you !

Paul Rãican
Paul Rãican
April 19, 2019 23:11
Reply to  Luce Sebastien

e) Rh1->f3 is, however, illegal position.

Luce Sebastien
Luce Sebastien
February 25, 2018 23:33

Another twin !
f) f7->h5
1…c4 2.c5 Qc2 3.h6 Qg6‡

Luce Sebastien
Luce Sebastien
February 25, 2018 23:52

Again another twin !
g) g7->g4
1…Sc3 2.e5 Se4 3.Se7 Sf6‡

Luce Sebastien
Luce Sebastien
February 26, 2018 00:05

One interesting info :
In club the mate of a) is named “Marmelade Mate” !
The explanation is that after the moves 1.e4 e5 2.Dh5, the player with white says “Oh but you have marmelade on your King e8 !” So the player with black touches his King to verify… And white says “You touched the King, you have to play it !”
So the end…

Andrew Buchanan
Andrew Buchanan
February 27, 2018 02:12

In b) might instead have history 1. Sh3 f5 2. Sf4 Kf7 and then both officers go home, bK triangulating. There’s another one with 1. Sc3 f6 2. Sd5 f5 3. Sf4 and now bS or bK make an even number of moves while wS returns home. I guess there is a kind of PRA here where you need to find a forward solution for each possible kind of retro history. Ronald Turnbull would love it. Does Jacobi allow for assignment of initial state? (A kind of move 0 as was done with Chess960.)

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