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No.1349 |
Original Fairy problems |
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No.1349 Arno Tüngler |
Solution: (click to show/hide) |
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white Ke8 Pa7d3d4f3h2h5
black Kd5 Qg7 Ba1b1 Rb2e3 Se6 Pc4c6f4g3h4h6
ser-!=66 (7+13) C? |
|
No.1349 |
Original Fairy problems |
|
No.1349 Arno Tüngler |
Solution: (click to show/hide) |
|
white Ke8 Pa7d3d4f3h2h5
black Kd5 Qg7 Ba1b1 Rb2e3 Se6 Pc4c6f4g3h4h6
ser-!=66 (7+13) C? |
what is the cook when the a-pawn is lower than a6 ?
For example: 1.Ke8 2.hxg3 3.gxf4 7.f8=B 8.Bb4 13.f8=B 14.Bfe7 18.Ka6 20.Bxh6 21.Bf4 24.h8=R 26.Rxc6 27.Rxc4 29.Ra8 30.Bb8 32.Ba5-c7 33.Ka7 35.a6 !=
So, with wPa6 that should already not be possible.
Is it so important to say « without capture « ?
Is there already a longer position « with captures » ?
Yes, the longest has 173 moves with and 119 moves without promoted force. See PDB P1333509 and P1273550. In long series-movers captures are usually quite important to get small changes in the position that add length.
cook 1.hxg3 2.gxf4 3.f5 4.f4 5.f6 6.f5 7.f7 8.f6 9.fxg7 10.a8=R 11.Ra4 12.Rxc4 13.Rxc6 14.Rxe6 15.Kf8 16.Rxh6 17.Rh8 18.h6 19.h7 20.Rg8 21.h8=B!=
Thanks to Václav for the cook that I should have seen…
Would like to correct this with wBd7 instead of wPa7 and one move shorter – a ser-!=65. The solution remains unchanged besides after 1.Bc8 2. Ba6 everything is one move less. Maybe you can test again?