Fairy chess composition
 No.1375  Sébastien Luce (France) Original Fairy problems JF-2019/I: January – June’2019

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 No.1375 Sébastien Luce France original – 20.02.2019 Solution: (click to show/hide) White Kg3 Black Kh1 Pa6c6d5e4b3b2e2h2 Neutral Pg2 h=9                                  (1+9+1) C- Neutral pawn g2 1.e2-e1=S Kg3-f2 2.Se1-f3 g2*f3 3.b2-b1=Q f3*e4 4.b3-b2 e4*d5 { } 5.Qb1-h7 d5*c6 6.Qh7-b7 c6*b7 7.b7-b5 b5*a6 { } 8.b2-b1=R a6-a7 9.Rb1-b7 a7-a8=nB {= (C- ; Impossible to test but probably correct (Author))} Only white King and neutral Pawn achieve black stalemate! AUW at the end/Pin stalemate. On move 7 neutral Pawn has to push back in b5 to capture a6. (Author) No.1375.1 Sébastien Luce France version of No.1375 – 13.03.2019 Solution: (click to show/hide) White Kg3 Black Kh1 Sa8 Pc6d5e4b3b2e2h2 Neutral Pg2 h=8                                  (1+9+1) C- Neutral pawn g2 1.e2-e1=S Kg3-f2 2.Se1-f3 g2*f3 3.b2-b1=Q f3*e4 4.b3-b2 e4*d5 { } 5.Qb1-h7 d5*c6 6.Qh7-b7 c6*b7 7.b2-b1=R b7*a8=nB+ 8.Rb1-b7 Kf2-f1 {= (C- ; Impossible to test but probably correct (Author))} Only white King and neutral Pawn achieve black stalemate! AUW at the end/Pin stalemate. (Author)

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ganapathi
February 22, 2019 08:47

Stalemate scene well planned! The double jump of the neutral P comes in handy and AUW is bonus!
Very enjoyable!

Georgy Evseev
February 22, 2019 12:43

1.g1NS Kf2 2.a5 NSxe2 3.d4 NSxd4 4.b1Q NSxb3 5.Qa1 NSxa5 6.Qb1 NSxc6 7.Qf1+ Kxf1 8.NSd4 NSf3 9.ef Kf2 =

Luce
February 23, 2019 21:47

Aie aie aie (in french) Georgy !
Please Julia, replace it by another problem waiting i re work it if possible.

Luce
February 23, 2019 22:01

Maybe it is possible to put a black bishop in e4 instead of a pawn but it is not so nice.
I think the best solution seems to inverse black g2 pawn and neutral e2 pawn with the sol. 1.g1=S Kf2 2.Sf3…
What do you think about it Georgy and Julia ?

Georgy Evseev
February 24, 2019 10:12

Inverse e2&g2 definitely will not work – black have free moves.
Be4 need more testing.

Luce
February 24, 2019 12:19

Yes you are right Georgy. To inverse e2 and g2 is cook with 1.e1=nS ?

Luce
February 24, 2019 13:28

Grrr… it is also cook with a black bishop in e4 with 1.g1=nS Kf2 2.b1=S Snxe2 3.d4 Snxd4 4.a5 Snxc6 5.Sd2 Snxa5 6.Snac4 Snxd2 7.Bg2 Snxb3 8.Snd2 Snf1 9.Bxf1 Kxf1=
Dear Georgy Julia I think the idea of the problem is definively cook. ?

Aleksandr Bulavka
February 24, 2019 17:51

bPe2nPg2 and wKg3->e1?

Aleksandr Bulavka
February 24, 2019 17:53

Exchange bPe2 and nPg2. And wKg3->e1?

Luce
February 25, 2019 17:28

Dear Alexandre unfortunately your proposition is also cook. The last attempt is to put a black bishop in d5 in the original position. I have to check it…

Luce
March 3, 2019 15:56

To save the idea of the problem 1375,
I propose the following version with a solution one move shorter. I invite all the composers of JF to see if there is a cook. Best to all

h=8
White : Kg3
Black : Kh1 Sa8 Pc6d5e4b3b2e2h2
Neutral : Pg2
Sol. :
1.e1=S Kf2 2.Sf3 gxf3 3.b1=Q fxe4 4.b2 exd5 5.Qh7 dxc6 6.Qb7 cxb7 7.b1=R bxa8=Bn+ 8.Rb7 Kf1 =

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