No.1453 
Hubert Gockel
(Germany)

Original Fairy problems
JF-2019/II:
July – December’2019


Definition: (click to show/hide)


No.1453 Hubert Gockel
Germany

original – 20.10.2019

Solution: (click to show/hide)

white Qc2 Pc3b6 Sd4 Rf5 Ka1 black Bh1 Ke3 Qa8 Pf3f4e5f7b7a6 Se4 Rf8

#2vv                                          (6+11)
Breton Adverse


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Kjell Widlert
Kjell Widlert
10 months ago

The logic is not as simple as one would think (which makes the problem all the more interesting). The Breton adverse condition allows White to remove any black P when capturing Pe5. So White sets up a threat by removing a guarding bP … no, that is true only for the solution! Rf5-e5 actually sets up two threats (Sf5#, Rxe4#), and the bP removals on b7 and f7 serve as dual-avoidance effects (Sushkov-theme style). The removal of Pf3 in the solution rules out both threats by dual-avoidance effects, but lets in a new threat by removal of a guard (so this is a form a threat correction, too).

The appearance of all three thematic mates in every phase works quite seamlessly. I’m especially impressed with how Sf5# and Rxe4# are produced in the solution.

Hubert Gockel
Hubert Gockel
10 months ago

I couldn’t have explained the contents better – so thank you very much, Kjell!