No.1531
Chris Feather
(England)

Original Fairy problems
JF-2020-II:
01.07.2020 - 31.12.2020


Definitions / Определения


No. 1531 Chris Feather
England
original - 19.08.2020

white Kh4 Bg3 Rg5 Sf4f5 black Ke5 Sd5d6 Pb7b6a4
h#2            2 solutions            5+6
Take & Make

Solution: (click to show/hide)


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Paul Raican
Paul Raican
August 25, 2020 00:44

Compare with this work of Eric Huber:
w: Kh1, Rc1, Rg6, Ba4, Bb4, Pc5, d5
b: Kg3, Rd2, Bg1, Bg4, Sh3, Pg5
1st Prize, Die Schwalbe TT206,2011
1.Bxc5-c6 Bxd2-h2+ 2.Kxh2-c7 dxc6-a8=Q#
1.Rxd5-d6 Rxg1-f2 2.Kxf2-f8 cxd6-d8=S#
Zilahi, exchange of functions.

Last edited 3 months ago by Paul Raican
Manfred Rittirsch
Manfred Rittirsch
August 28, 2020 16:21

As indicated by Chris, the matrix with double king transfer in each solution was used before. The profoundly improved economy (including model mates) is in fact the major achievement here.
Chris Feather, Fairings 2011, W: Ke7 Rd7 Bf7f3 Sd6e6 – B: Kd5 Be2 Pç7g6e5e4g2, h#2 2.1.1.1 Take & Make, 1.Kxe6(Kg7) Bxe2(Bb5) 2.Kxf7(Kd5) Sb7# & 1.Kxd6(Kç8) B×g2(Bg1) 2.Kxd7(Kd5) Sd8#
Pierre Tritten, 1° Commendation Phénix 2012, W: Ke8 Rf6 Bf4 Se6e5 Pd4 – B: Kd6 Pf3, h#2 2.1.1.1 Take & Make, 1.Kxe5(Kg4) Kd8 2.Kxf4(Kd6) Sf4# & 1.Kxe6(Kg7) d5 2.Kxf6(Kd6) Sd3#
Chris Feather, Fairings 2014, W: Kb1 Rd4 Bf4 Sd5e5 Ph4f2 – B: Kd6 Rh6 Ba4e1 Sa8 Pf7b6f6ç5a3f3e2, h#2 Take & Make b) Pf6->f5, a) 1.Kxe5(Kg4) Txa4(Td7) 2.Kxf4(Kd2) Sxb6(Sb5)# b) 1.Kxd5(Kç3) Bxh6(Bd6) 2.Kxd4(Kf4) Sxf7(Sf6)#