No.1551
Dirk Borst
(Netherlands)


(v) 1551.1 Dirk Borst (Netherlands)
(v) 1551.2 Dirk Borst (Netherlands)
(v) 1551.3 Dirk Borst (Netherlands)
(v) 1551.4 Dirk Borst (Netherlands)


Warm welcome to Dirk!

Original Fairy problems
JF-2020-II:
01.07.2020 - 31.12.2020


Definitions / Определения


No. 1551 Dirk Borst
Netherlands
original - 27.10.2020

White Kc1 Be1 Pc3b5g6 Black Kf1 Be8g3 Se3e4 Pa5b7c4d5d6h2g7
ser-s#21                       5+12
Circe Rex Inclusiv

Solution: (click to show/hide)


No. 1551.1 Dirk Borst
Netherlands
version of No.1551 - 06.11.2020

White Kc1 Be1 Pc3b5g6 Black Kf1 Be8g3 Se3e4 Pa5b7c4d5d6h2g7e7
ser-s#21                       5+13
Circe Rex Inclusiv

Solution: (click to show/hide)


No. 1551.2 Dirk Borst
Netherlands
version of No.1551 - 29.12.2020

White Kb1 Be1 Pc3b5g6d2h4 Black Kf1 Be8 Se3e4 Pa5b7c4d5d6h2g7g3
ser-s#22                       7+12
Circe Rex Inclusiv

Solution: (click to show/hide)


No. 1551.3 Dirk Borst
Netherlands
version of No.1551 - 28.02.2021

white Be1 Pd3d2a4g6 Kb2 black Kf1 Pg3h2d4a5d6b7g7 Sh4e4 Be8
ser-s#25                       6+11
Circe Rex Inclusiv

Solution: (click to show/hide)


No. 1551.4 Dirk Borst
Netherlands
version of No.1551 - 17.01.2022
dedicated to Arno Tüngler

white Kb2 Be1 Pb5d2g6 black Kf1 Bb6e8 Se4h4 Pd3d4d6g3g7h2
ser-s#23                       5+11
Circe Rex Inclusiv

Solution: (click to show/hide)



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Arno Tüngler
Arno Tüngler
November 2, 2020 14:53

Nice idea and difficult solution but seems also to go with 11.Qxg7 13.Qd2 15.g8=S 17.Sxe8(Bc8) 19.Kh3 20.Qg2+ Ke1# or did. I overlook something? This avoids going through g2 and so there is no need to free e8.

Kjell Widlert
Kjell Widlert
November 5, 2020 04:12
Reply to  Arno Tüngler

You overlooked 21.Sxd6(+Pd7)!

Kjell Widlert
Kjell Widlert
November 5, 2020 04:26
Reply to  Kjell Widlert

… but we have one move to spare, so 10.Qxd6(Pd7) 11.Qxd7 12.Qxg7 etc until 21.Qg2+ Ke1# should work – or am I overlooking something now??

Dirk Borst
Dirk Borst
November 5, 2020 21:02

Yes, Kjell is right: that is a cook. The easiest fix seems to be: + bPawn e7, which prevents 12.Qd7xg7.

Arno Tüngler
Arno Tüngler
November 29, 2020 11:28

Seems now to be cooked with Dual 11.Qh8 12,Qxh2(Ph7) 13.gxh7 14.h8=R 15.Re8 16.Bd8 18.Kh3 19.Qg2+ Ke1# due to the bPe7 or did I overlook something again?

Dirk Borst
Dirk Borst
December 28, 2020 23:57
Reply to  Arno Tüngler

No, you are right: square e7 cannot be occupied (a fact I had forgotten).
I sent a new correction to Julia today

Arno Tungler
Arno Tungler
January 28, 2021 21:18
Reply to  Dirk Borst

Here is a cook due to the wPd2: 7.Kh3 9.dxc4(Pc7) 11.bxc7 12.c8=Q 13.Qd7 15.cxd6 16.Qa4 18.dxe8=S(Bc8) 19.Ba7 21.Qg2+ Ke1#

Dirk Borst
Dirk Borst
January 28, 2021 22:46
Reply to  Arno Tungler

Hahaha this is terrible! And you have a move to spare… I will have to work even harder 😉