No.1551
Dirk Borst
(Netherlands)


(v) 1551.1 Dirk Borst (Netherlands)
(v) 1551.2 Dirk Borst (Netherlands)


Warm welcome to Dirk!

Original Fairy problems
JF-2020-II:
01.07.2020 - 31.12.2020


Definitions / Определения


No. 1551 Dirk Borst
Netherlands
original - 27.10.2020

White Kc1 Be1 Pc3b5g6 Black Kf1 Be8g3 Se3e4 Pa5b7c4d5d6h2g7
ser-s#21                       5+12
Circe Rex Inclusiv

Solution: (click to show/hide)


No. 1551.1 Dirk Borst
Netherlands
version of No.1551 - 06.11.2020

White Kc1 Be1 Pc3b5g6 Black Kf1 Be8g3 Se3e4 Pa5b7c4d5d6h2g7e7
ser-s#21                       5+13
Circe Rex Inclusiv

Solution: (click to show/hide)


No. 1551.2 Dirk Borst
Netherlands
version of No.1551 - 06.11.2020

White Kb1 Be1 Pc3b5g6d2h4 Black Kf1 Be8 Se3e4 Pa5b7c4d5d6h2g7g3
ser-s#22                       7+12
Circe Rex Inclusiv

Solution: (click to show/hide)



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Arno Tüngler
Arno Tüngler
November 2, 2020 14:53

Nice idea and difficult solution but seems also to go with 11.Qxg7 13.Qd2 15.g8=S 17.Sxe8(Bc8) 19.Kh3 20.Qg2+ Ke1# or did. I overlook something? This avoids going through g2 and so there is no need to free e8.

Kjell Widlert
Kjell Widlert
November 5, 2020 04:12
Reply to  Arno Tüngler

You overlooked 21.Sxd6(+Pd7)!

Kjell Widlert
Kjell Widlert
November 5, 2020 04:26
Reply to  Kjell Widlert

… but we have one move to spare, so 10.Qxd6(Pd7) 11.Qxd7 12.Qxg7 etc until 21.Qg2+ Ke1# should work – or am I overlooking something now??

Dirk Borst
Dirk Borst
November 5, 2020 21:02

Yes, Kjell is right: that is a cook. The easiest fix seems to be: + bPawn e7, which prevents 12.Qd7xg7.

Arno Tüngler
Arno Tüngler
November 29, 2020 11:28

Seems now to be cooked with Dual 11.Qh8 12,Qxh2(Ph7) 13.gxh7 14.h8=R 15.Re8 16.Bd8 18.Kh3 19.Qg2+ Ke1# due to the bPe7 or did I overlook something again?

Dirk Borst
Dirk Borst
December 28, 2020 23:57
Reply to  Arno Tüngler

No, you are right: square e7 cannot be occupied (a fact I had forgotten).
I sent a new correction to Julia today