Original Fairy problems
JF-2021-I:
01.01.2021 - 30.06.2021
No. 1622 Aleksey Oganesjan
Russia
original - 12.06.2021
black Pb2g3d6 Kf3 Ra4a6
white Ra2 Qh3 Bg5 Kb5 Sf6
hs#2 4 solutions 5+6
Solution: (click to show/hide)
No. 1622.1 Aleksey Oganesjan &
Sergey Shumeiko
Russia
version of No.1622 - 25.07.2021
black Qg1 Sf1 Pa2 Bh5 Kc5
white Ke1 Rb4b6 Bg8 Qb8
hs#2 4 solutions 5+5
Solution: (click to show/hide)
Neat idea to differentiate queen promotion !
Congratulations Aleksandr for this nice improvement ! AUW is always an important theme in help genres.
Sebastien
Sorry Congratulations Aleksey ! 🎖
Sebastian, You can edit your post (provided nobody has replied to it!). No need for a “correction post”!
This requires a delicate mouse dance: move your mouse to the lower right of your post. Click the Gear icon(“Manage Comment”) when it is visible. Then click the “Edit” label.
It’s easy to tranform an age-old s#2 to show the hackneyed AUW in a hs#2.
For example: Alain C. White, The Pittsburgh Gazette Times, 1916 (!), Variation D. Papack;
Ke5, Qh8, Rd6, Rh2, Ba2, Ba3, Sb5 (7); Kc2, Qf7, Ra5, Rc8, Bb8, Bg2, Se6, Pc3, Pe2 (9);
hs#2, 4 solutions.
Initial Alain’s problem – https://yacpdb.org/#262521
In hs#-genre there are very strict requirements to loading of both White and Black pieces in each solution (see an article of P. Petkov – https://juliasfairies.com/articles/pap-hs-its-very-interesting).
But in your hs#-“variation”, except completely technical bRc8 and partially technical bSe6 (that is necessary only in two solutions), there are three (!!!) fictitious pins – two Black and one White – that are unnecessary in two or three solutions. It can be forgiven in s# but it is unacceptable in hs#!
The black AUW in a hs#2 is a simplified s#2. 100 years later I’m unable to see
any intrinsic value.
Then the Babson task has no intrinsic value in the way you put it. All chess problems, published and unpublished, consume time to create. Chess problems and puzzles are a centuries old art and hobby; every diagram created has value to someone, somewhere.
Since hs#2 has four solutions, it means that White execute four first moves and four second moves. So hs#2 is a transformed s#3 (not s#2!).
But s#3 strongly differs from hs#2 – Black opposes on 1st, 2nd and 3rd moves, while in hs#2 Black oppose only on 2nd move.
And after all: transformations of the same ideas from one genre into another always deserve an attention! Otherwise it can be said: “Oh, Novotny theme was already realized in #2, so its realization in another genres has no intrinsic value”.
Actually I have seen just two s#2s ( one of them by Milan Vikcevic) with different replies to four black promotions on the same square — without checking key. I don’t think it was done frequently.
Thank you M.Shankar Ram for the information.