Original Fairy problems
JF-2021-II:
01.07.2021 - 31.12.2021
No. 1655 Neal Turner
Finland
original - 25.09.2021
white Royal ge2
white Rf2 Pg4 Bf8a2
black Royal gf5
black Ph3g5f7a5c3b2 Bf6 Sh7 Ra3
s#2 5+10
SAT
Royal Grasshopper e2, f5
SAT
Royal Grasshopper e2, f5
Solution: (click to show/hide)
The combination of SAT and RoyalG make it difficult to grasp the concept even when one sees the solution. Motivation for the key and defence Sxf8 took some time to understand. The Try Bc5? and it’s appearance after Rb3 make a neat Dresden. Wish there were two such delicacies than just one 😀. Kudos Neal Turner
“Wish there were two such delicacies than just one.”
I’m working on it – it’s not easy!
The threat 2.Bxf7+ rGxf7 provides the wrG with a flight on h5. This doesn’t work before the key because of 3.Rf3!, which closes the line e2-h5.
The defence 1…Rb3 closes the line a2-f7, but this means there is no white guard of d5, so after 2.Bc5+ the set 2…Be5?? is illegal as the brG has a flight on d5. Instead Black is forced to play the substitute defence 2.Rb5 (so that the brG no longer has a flight on b5), but this is mate because the wrG has a flight on a6.
The defence 1…Sf8 blocks f8, so that after 2.Bxf7+? Black can just play 2…B~ and the brG will not have a flight to f8. However now after 2.Rxh3+ the move 2…rGxh3 is legal, because it doesn’t give the brG a flight on h8.The wrG is mated because it has a flight on h5.
Of course it will be difficult! None of your problems are easy to compose or grasp 😀