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Original Problems, Julia’s Fairies – 2013 (III): September- December
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No.384 – Ralf Krätschmer – A very nice reciprocal anti-batteries! (JV)
PAO(PA): Moves as Rook, but captures only by hopping over a hurdle to any square beyond.
VAO(VA): Moves as Bishop, but captures only by hopping over a hurdle to any square beyond.
No.384 Ralf Krätschmer
hs#2,5 b) Pad4->a8 (5+8)
VAOs: f6, f1
PAOs: e8, d4
Solutions: (click to show/hide)
a) 1…PAd4-b4 2.VAf6-d4 VAf1-c4 3.PAe8-e5 + PAb4xd4 #
b) 1…PAa8-a5 2.PAe8-a8 VAf1-a6 3.VAf6-d8 + PAa5xa8 #
(С+ Popeye 4.63)
It is impossible in some schemes, but I prefer twins in which it is NOT readily apparent why the other solution does not work. This nice problem unfortunately suffers from the comparison of precedents in the 9th WCCT award !
Nice black moves towards wK with switchback mates. There is at least one 9th-WCCT problem (I.Kirchner, 18th-20th pl.) with a similar content but with the more complex reciprocal functions of black pieces.
Here, the twin with moving the thematic bPA makes the black play rather artificial. And bVAf1 is twice only a hurdle. Such use of a fairy piece is worse than it would be of an orthodox bBf1 (which, by the way, could guard b5 in a Meredith).
Reciprocal black play with the mutual interferences on the same square (anti-Grimshaw) would add complexity, compared to the Kirchner’s problem. A couple of examples:
Hs#2.5 Twin Move a1 c1
Hs#3.5 Twin Move e2 a2
The second example could easily have 2 solutions with 2 or 3 extra Pawns.