 No.564, 564.1 Ladislav Packa (Slovakia) Warm welcome to Ladislav! |
Original Problems, Julia’s Fairies – 2014 (II): May – August →Previous ; →Next ; →List 2014(II) Please send your original fairy problems to: julia@juliasfairies.com |
No.564 by Ladislav Packa – A nice Anti-Circe PG! (JV)
No.564.1 by Ladislav Packa – A new version to No.564 with a twin! (JV)
Definitions:
Anti-Circe Calvet (the default type): After a capture the capturing piece (Ks included) must immediately be removed to its game array square (necessarily vacant, else the capture is illegal). Captures on the rebirth square are allowed. Game array squares are determined as in Circe.
Circe: Captured units (not Ks) reappear on their game-array squares, of the same colour in the case of pieces, on the file of capture in the case of pawns, and on the promotion square of the file of capture in the case of fairy pieces. If the rebirth square is occupied the capture is normal.
Vertical Mirror Anti-Circe: same as Anti-Circe, except that the rebirth square is on the vertical mirror from the normal place.
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No.564 Ladislav Packa |
Solution: (click to show/hide) |
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white Bf1c1 Ke1 Qd1 Ph2g2f2e2d2c2b2a2 Sg1b1 Rh1a1
black Bf8c8 Ke8 Qd8 Ph7g7f7e7d7c7b7a7 Sg8b8 Rh8a8
PG in 6.0 ( 14 + 16 ) |
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No.564.1 Ladislav Packa |
Solutions: (click to show/hide) |
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white Bf1c1 Ke1 Qd1 Ph2g2f2e2d2c2b2a2 Sg1b1 Rh1a1
black Bf8c8 Ke8 Qd8 Ph7g7f7e7d7c7b7a7 Sg8b8 Rh8a8
PG in 6.0 ( 14 + 16 ) |
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At first I didn’t see the exchange KQ in the diagram position and constructed the dualistic “solution” 1.c4 Sf6 2.c5 Se4 3.c6 Sxc6 (Sg8) 4.Qa4 Sc3 5.b3 Sb5 6.Ba3 Sxa3(Sb8)
It makes me think that the problem is nice but would become outstanding with a twinning:
a) At-home black position
b) Ke8<->Qd8
Obviously the solution would show an interchange
Sb8<->Sg8 in a) and a pair of crossed Pawn captures in b).
Nicolas:
I must say that I thought the twins, although thematically identical to the solution. Changing conditions for example Symmetry Anticirce might have something to bring. You do not want to try it?
As I never worked under Anticirce, I will not begin with a too difficult theme, but maybe I will try this condition alone in PG, the dozen of examples found in WinChloe lets some possibilities, it seems…
Many thanks for the kind dedication of this excellent problem, Laco!
Is the second condition programmed? (Popeye seems to don’t accept cond verticalmirroranticirce).
Julia, there is a wPd2 in the diagram position.
Yes, Nicolas, there should be wPd2 for diagram position. With animation of solution it shows the position of the last move of b) 6…cxd4 (Pd4→e7). I’ll check with D.Turevski (author of Py2Web animation) how to change it to the last move of a) for the initial position.
Yes, with control of correctness are difficulties (see C-). This fairy condition knows WinChloe (under the name Anticirce inverse), but checking of short SPG takes forever.
Maybe you should ask Thomas Maeder if he might program “anticirce inverse”, as there is great hope for Popeye to be able to fully check this 6.0 game.
Btw I have something in mind for an Anticirce PG, but not yet finalized…
Popeye v4.67 supports many combinations of Circe and AntiCirce. VerticalMirrorAntiCirce can be specified as follows:
condition AntiCirce VerticalMirror
Here is the Popeye code.
pieces
white ke1 qd1 ra1 rh1 sb1 sg1 bc1 bf1 pa2b2c2d2e2f2g2h2
black ke8 qd8 ra8 rh8 sb8 sg8 bc8 bf8 pa7b7c7d7e7f7g7h7
stipulation ha=>b6
pieces
white ke1 qa4 ra1 rh1 sb1 sg1 bf1 pa2b3e2f2g2h2
black kd8 qe8 ra8 rh8 sb8 sg8 bc8 bf8 pa7b7c7d7e7f7g7h7
condition AntiCirce VerticalMirror
option WhiteToPlay
Popeye finds many cooks e.g.
1.b2-b3 e7-e5 2.Bc1-a3 Qd8-h4 3.Ba3-e7 Ke8*e7[bKe7->d8] 4.d2-d4 e5*d4[bPd4->e7] 5.Qd1-d4 Qh4-e4 6.Qd4-a4 Qe4*c2[bQc2->e8]
Thank you, Geoff!
For the verification of correctness, but mainly for the information how to work with Popeye.
I am very sorry that I dedicated the incorrect composition to Nicolas…
For interchanges of pieces, see M. Caillaud, Prize, Nunspeet 2000: 1. e4 c6 2. e5 Qa5 3. e6 Kd8 4. d3 Qc3 5. exd7(Pd2) Bh3 6. d4 Sd7 7. d5 Rc8 8. d6 Rc7 9. dxe7(Pe2) Se7 10. Sa3 Sg6 11. Sb5 Ba3 12. Sf3 Sdf8 13. Sg5 Re7 14. Sxh7(Sb1) Rh7 15. Sxa7(Sg1) Sh8.