Fairy chess composition

# No.622 (LP)

 No.622 Ladislav Packa(Slovakia) Original Problems, Julia’s Fairies – 2014 (III): September – December →Previous ; →Next ; →List 2014(III) Please send your original fairy problems to: julia@juliasfairies.com

No.622 by Ladislav Packa – Short, but interesting idea showing Disparate condition in PG problem! (JV)

Definition:

Disparate: If one side makes a move with a piece of type “x” (black, white,neutral, half-neutral, etc., King included), the other side cannot answer immediately by moving a piece of the same type “x”.). A pawn promoting is a pawn move. (Popeye’s interpretation)

 No.622 Ladislav PackaSlovakiaoriginal – 12.10.2014 Solution: (click to show/hide) white Bf1c1 Ke1 Qd1 Ph2g2f2e2d2c2b2a2 Sg1b1 Rh1a1 black Bf8c8 Ke8 Qd8 Ph7g7f7e7d7c7b7a7 Sg8b8 Rh8a8 PG5                                   (16+16)Disparate (Py) 1.e2-e4 Sb8-c6 2.Qd1-f3 e7-e5 3.Bf1-e2 Qd8-f6 4.Ke1-f1 Bf8-e7 5.Sb1-c3 Ke8-f8 {dia (C+ by Popeye 4.69)} Symmetrical position is achieved by cyclic shift of types of moving units: P-Q-B-K-S respectively S-P-Q-B-K. (Author)

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seetharaman
October 12, 2014 22:58

Interesting. But the fairy condition merely eliminates cooks!

Dmitri Turevski
October 13, 2014 07:02

They all seem to be thematic tries here.

Kjell Widlert
October 13, 2014 15:55

White and Black have to play exactly the same moves. Each side has 5 possible sequences (the S move can occur at any half-move, the others are fixed), but the condition dictates that only one sequence works for each side – and it’s not the same sequence. The necessary distance between White and Black is kept by having Black playing the S move first, and White playing it last.

The idea clearly justifies the condition.

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