Fairy chess composition

# No.786,787 (MG)

 No.786, 787 Michael Grushko (Israel) Original Problems, Julia’s Fairies – 2015 (I): January – June    →Previous ; →Next ; →List 2015(I) Please send your original fairy problems to: julia@juliasfairies.com

No.786, 787 by Michael Grushko – Two four-men with a nice play of neutrals! (JV)

Definitions:

Phantom Chess: Any unit except a king may move either normally (from its current square) or as though from its Circe rebirth square if the latter is vacant.

Parrain Circe: After a capture, the captured piece is reborn only after another piece of its own side has moved. The line between capturing square and rebirth square is parallel with and of same direction and length as the move of this other piece. Pawns can be reborn on 1st and 8th rank. From their own base rank, they may move one-step; if reborn on the promotion rank, the Pawn at once promotes, the promotion piece being determined by the Pawn side.

 No.786 Michael GrushkoIsraeloriginal – 28.04.2015 Solutions: (click to show/hide) Black Ke5 Neutral Be4 Sd5 Sd2 h#3              2 solutions      (0+1+3)Parrain CircePhantom Chess(no white King) 1.nSd2*e4 nSd5-e3[+nBf2] 2.Ke5-f4 nSe3-g4 + 3.Kf4*g4 nSe4-f6[+nSh6] # 1.nBe4-f3 nSd2*f3 + 2.Ke5-e4[+nBf2] nBf2-e1 3.Ke4*f3 nSd5-f6[+nSh4] # { (C+ by Popeye 4.69)} No.787 Michael GrushkoIsraeloriginal – 28.04.2015 Solutions: (click to show/hide) Black Ke5 Neutral Bd2 Sf4 Sc2 h#2,5          b) Bd2→f3      (0+1+3)Parrain CircePhantom Chess(no white King) a) 1...nSc2*d2 {display-departure-square} 2.Ke5*f4[+nBe1] nBe1-b2[+nSc5] {display-departure-square} 3.Kf4-e3 nSd2-h3 #{display-departure-square} { (full moves: 1...nSc2-b1*d2 ; 2...nBe1-c1-b2 ; 3...nSd2-g1-h3 #)} b) nBd2-->f3 1...nSc2-d4 2.Ke5*d4 nSf4-e2[+nSc2] + 3.Kd4-d3 nSe2-a3 #{display-departure-square} { (full move: 3...nSe2-b1-a3 #) (C+ by Popeye 4.69)}

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Joost de Heer
April 29, 2015 20:29

How is the rebirth defined in case of a ‘phantom move’? E.g. after 1. nSxe4 nSd5->b1-a3, is the bishop reborn on d6 (translation vector is b1-a3) or b2 (translation vector is d5-a3)?

Eric Huber
May 1, 2015 11:47
Reply to  Joost de Heer

The answer is provided in 787, twin a) by the second move 2.Kxf4 (+nBe1) nBe1-b2 (+nSc5) : the translation vector is e1-b2 and not c1-b2.
So in your example, the vector is d5-a3 and not b1-a3.

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