Julia's Fairies

No.825 (NSR)

No.825, 825.1 
N.Shankar Ram (India)

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Original Problems, Julia’s Fairies – 2015 (I): January – June

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No.825 by N.Shankar Ram – A rare guest on JF: reflexmate with multiphasic thematic play! (JV)

No.825.1 by N.Shankar Ram – A revised version to No.825 – “position is now legal (and one piece lighter)”. (Author)


No.825 N.Shankar Ram
India

original – 08.06.2015

Solutions: (click to show/hide)

White Ka5 Rf3 Bb5 Bh2 Se7 Pf6 Ph7 Pd7 Pf5 Pe4 Pc3 Pf2 Pc7 Black Kc5 Qd2 Rh6 Rh4 Bc8 Be1 Pa6 Ph3 Pc2 Ph5 Pa4

r#2            2 solutions        (13+11)


No.825.1 N.Shankar Ram
India

version to No.825 – 25.08.2015

Solutions: (click to show/hide)

White Ph7c7e4f5f6d7c3 Se7 Bh2b5 Ka5 Rf2f3 Black Qd2 Pa4a6h3h5 Rh4h6 Bc8e1 Kc5

r#2           2 solutions       (13+10)


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seetharaman
seetharaman
June 9, 2015 20:05

Marvellous problem showing two of his favorite themes – R# and Cyclone! Pity the double refutation is unavoidable in the first try. Welcome back to form Shankarram. When he joins our small WCCT team, we will surely do far better than 9-WCCT !

Kjell Widlert
Kjell Widlert
June 9, 2015 22:35

What a matrix!
I’m sorry to say the position is “illegal”, i.e. not possible to reach from the game array. White pawns have captured at least 7x, and Black has 11 pieces left.

shankar ram
shankar ram
June 10, 2015 03:02
Reply to  Kjell Widlert

Yes, I’m aware of that.. the matrix is bit “plug hungry “.
Paradoxically, it could be made “legal ” by using a few promoted pieces!

Georgy Evseev
Georgy Evseev
June 10, 2015 16:52

A great concept!

But just by exchanging places of Ph7 and Ph3 it is possible to have one solution and a single refutation in any try.

It is probably author’s desire to keep phase 1.e5! as a solution (as it has most varied play), and I want to believe that it should be possible to reach a version with a single solution and non-repeating refutations…

shankar ram
shankar ram
June 10, 2015 17:27

Thank you, Georgy!
But, as you observed, I wanted to retain 1.e5 as a key..
And the illegality of the position still remains.. though I wouldn’t lose much sleep over it.
As you indicate, an ideal setting would have:
– 1. e5 as key
– No dual refutations
– No repeated refutations
– Single solution.. though I’m OK with 1.Bd3 as an additional solution – I feel keeping a key from the 2nd cycle would help a solver discover the 2nd cycle.. Maybe this sounds a bit like making a virtue out of a necessity!

Kjell Widlert
Kjell Widlert
June 10, 2015 22:13
Reply to  shankar ram

To me, it seems quite natural to have one solution from each cycle. Who says reflexmates should have just one solution, and helpmates should preferably have two solutions? (All right, I’m aware you can’t have the same kind of tries in a helpmate…)

shankar ram
shankar ram
June 10, 2015 17:58

Sometimes one gets lucky. The same theme in a different genre, with all the ideal requirements: http://pdb.dieschwalbe.de/search.jsp?expression=PATTERN+%3D%27sTe8+sKd6+wKf6+wTc4+sLe1%27+AND+A+%3D+%27Shankar+Ram%27

seetharaman
seetharaman
June 10, 2015 23:05

I think illegality is easily rectified by moving WPf6 to g7.

Kostas Prentos
Kostas Prentos
June 10, 2015 23:21
Reply to  seetharaman

I don’t know how the content is influenced, but moving the wPf6 to g7 does not make the position legal. The white pawns still need 6 captures, with only 5 black men missing.

seetharaman
seetharaman
June 11, 2015 06:31
Reply to  Kostas Prentos

ooh … bad arithmatic 🙁

shankar ram
shankar ram
June 11, 2015 08:18

I think you meant WPf6 to g6, not g7 ..

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