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No.898 |
Original Problems, Julia’s Fairies – 2015 (II): July – December →Previous ; →Next ; →List 2015(II) Please send your original fairy problems to: julia@juliasfairies.com |
No.898 by Geoff Foster – Nice and light demonstration of Relaxed Symmetry Anti-Circe condition in a play to all four corners! (JV)
Definitions:
Anti Take & Make: Every capture (“take”) must be complemented by a further step (“make” which is not a capture) by the captured piece (Kings excluded), which must move from its square of vanish (according to the wishes of the capturing side in case of options). The capture is forbidden if the captured unit has no possible moves. Promotions at the end of the “make” element are normal.
Relaxed Symmetry Anti-Circe: ‘Relaxed’, which is the opposite of ‘Strict’, means that a capture can still take place even if the rebirth square is occupied (in relaxed Anti-Circe, if the rebirth square is occupied then the capturing unit disappears from the board). (implemented in the latest version of Popeye, 4.73)
Anti-Circe: After a capture the capturing piece (Ks included) must immediately be removed to its game array square (necessarily vacant, else the capture is illegal). R, B & S go to the square of the same colour as the capture; Ps stay on the file of capture; fairy pieces go to the promotion square of the file of capture.
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No.898 Geoff Foster |
Solutions: (click to show/hide) |
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White Ke4
Black Kb2
Neutral pb7g7
h#2 3 solutions (1+1+2) |
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The stipulation should be h#2 (not hs#2)!
Sorry, of course h#2, corrected, my mistake!
Great find!
In the solution, the make part is indicated with a + and the Circe rebirth by a ->. Shouldn’t it be the other way round?
The symmetry anti-circe is not clear to me. In the second solution on the mating move, if the black king captures the NQ, (which it should to escape check) where will the black king reappear?
In the second solution, if the black king would capture the neutral queen:
– The neutral queen makes a queen move from a2, so will end up on a3…a8, a1, etc
– The black king will end up on h7 (symmetrical anticirce countersquare of a2)