No.222 
Valerio Agostini &
Gabriele Brunori

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Original Problems, Julia’s Fairies – 2013 (I): January – April

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No.222 – h#2,5 by Valerio Agostini & Gabriele Brunori – An elegant Grimshaw interpretation! (JV)

No.222.1 – h#2 by Valerio Agostini – A new version of No.222 composed after comments! (JV)


Definitions:

Grasshopper(G): Moves along Q-lines over another unit of either color to the square immediately beyond that unit. A capture may be made on arrival, but the hurdle is not affected.

PAO(PA): Moves as Rook, but captures only by hopping over a hurdle to any square beyond.

VAO(VA): Moves as Bishop, but captures only by hopping over a hurdle to any square beyond.

Lion(Li): Moves along Q-lines over another unit of either color to any square beyond that unit. A capture may be made on arrival, but the hurdle is not affected.


No.222 Valerio Agostini & Gabriele Brunori
Italy
original-10.01.2013
 
222-h#2,5-va-gb
h#2,5             2 solutions             (7+5)
Grasshopper e8
Pao h8
Vao e7
 
 
Solutions: (click to show/hide)
 
No.222.1 Valerio Agostini
Version of No.222
original-27.01.2013
 
222.1-h#2-va
h#2             2 solutions             (3+4)
Lion a4
 
 
Solutions: (click to show/hide)
 

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seetharaman
seetharaman
January 22, 2013 04:05

Elementary grimshaw shown many times in orthodox helpmates. Three hoppers and no Anti-battery mates !

Nikola Predrag
Nikola Predrag
January 22, 2013 10:17
Reply to  seetharaman

Yes, move bPg3->h3, add bPc5, remove wPs d4&f4 and replace w PA/VA by w R/B.

Dmitri Turevski
Dmitri Turevski
January 22, 2013 10:52
Reply to  Nikola Predrag

It’s a pity 2.Bf1 is a pure hideaway, but 2.Re1 is also a selfblock. Perhaps it could be rearranged? Scheme:
[img]http://www.yacpdb.org/xfen/?8/5R2/b2r3B/8/1p4K1/2k5/P7/3(Q2)1(Q2)2[/img]
h#2 2.1…
1.Bxf1 Bc1 2.Rd3 Rc7#
1.Rxd1 Rf2 2.Bd3 Bg7#
Can this be turned into h#2.5 with a single grasshopper?

seetharaman
seetharaman
January 22, 2013 14:01

Very nice. I think but for cooks h#2.5 would be very nice!

Nikola Predrag
Nikola Predrag
January 22, 2013 21:33
Reply to  seetharaman

Indeed very nice. Still I don’t like the static Grasshoppers, the play is not fairy. The accidental captures help to get rid of superfluous white material, cleverly done but perhaps not fully justifying these fairy pieces. White Knights on a5&c2 would do the job of Grasshoppers and Pawns.

Nikola Predrag
Nikola Predrag
January 28, 2013 18:22
Reply to  Julia

Battery/antibattery mates are results of the departure/arrival effects of a FRONT piece/hurdle, not of the arrival effect of a REAR piece. That was the first remark by Seetharaman. Therefore 222 is not a genuine fairy problem.

Nevertheless, the reciprocal functions of thematic white pieces is good but it is lost in the version, which is also not the most economical. First, wLI could be replaced by wG in 1st solution. So wKa5 and wGb4 would be more economical. Second, the power of wQ is not used enough and bPe5 is added. A rough example:

White Qb8 Kb4 Gd3; Black Re7 Bc6 Kd4; h#2; 2 sol
1.Bf3 Gg3 2.Re4 Qd6#; 1.Re3 Gf3 2.Be4 Qh8#

Direct & indirect antibattery with reciprocal mate/guard function in next example, still do not justify enough the presence of Chameleon piece:

White chameleon Qa4; White LIh7 Kb4; Black Re8 Bh6 Kd3
h#2.5 2 sol
1…LIh4 2.Bd2+ Kb3 3.Re3 cQf4=cS#; 1…Kc5 2.Re2 Kd5 3.Be3 cQe4=cS#