No.294, 295
Nikola Predrag (Croatia)

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Original Problems, Julia’s Fairies – 2013 (I): January – April

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Please send your original fairy problems to: julia@juliasfairies.com


DSCN3274-cropThese two problems by Nikola Predrag were firstly presented in the comments to No.289 and now I’m happy to show them here and thankful for the dedication to the 1st birthday of Julia’s Fairies:

No.294 – This problem same as the next one shows author’s thoughts about Popeye’s interpretation of Isardam condition;

No.295 – Author has written about it: “My dedication for the anniversary is pointed to the theoretical discussions on Julia’s site. It is an example with a question: “Is the Popeye’s treatment of Isardam authentic?” ” or “is Popeye’s Isardam a standard interpretation of this condition (concerning the netral pieces) or it could be accepted as a new variant of Isardam?

(JV)


Definitions:

Isardam: The moves causing a Madrasi-like paralysis are illegal. This holds right up to the capture of the mated King. This is standard form of Isardam.

Nightrider(N): A Rider along a straight line on squares lying a Knight`s move away from each other.

Grasshopper(G): Moves along Q-lines over another unit of either color to the square immediately beyond that unit. A capture may be made on arrival, but the hurdle is not affected.


No.294 Nikola Predrag
Croatia
original-10.04.2013
Dedicated to the 1st Birthday of Julia’s Fairies
 
294-h#2-np
h#2                 Isardam          (2+2+1)
b) -bNd6
c) bKb5->e4 (2 solutions)
Nightrider d6
(Popeye C+)
 
 
Solutions: (click to show/hide)
 
No.295 Nikola Predrag
Croatia
original example-10.04.2013
Dedicated to the 1st Birthday of Julia’s Fairies
 
295-h#2-np
h#2                 Isardam          (3+3+1)
b) nPh7->a2
Nightrider a4
Grasshopper f5
(Popeye C+)
 
 
Solutions: (click to show/hide)
 

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Janos Mikitovics
Janos Mikitovics
April 12, 2013 03:21

Here is a funny combination:

White Pd7 Kf6
Black Ka7 Nd6
Neutral Pf7
h#2 Py/C+
a) Isardam / 4 solutions
b) Isardam + PWC + Take & Make

a1) 1.Nd6-e8 + nPf7*e8=nQ 2.Ka7-b6 d7-d8=Q #
a2) 1.Nd6-c8 nPf7-f8=nN 2.nNf8-g6 d7*c8=N #
a3) 1.Ka7-b7 nPf7-f8=nS 2.nSf8-e6 d7-d8=S #
a4) 1.Ka7-b6 nPf7-f8=nB 2.nBf8-e7 + d7-d8=B #

b) 1.Nd6-e8 + Kf6*f7-f5 [+nPf6] 2.Ne8*f6-f7 [+nPe8=nR] d7*e8-d8=R [+nRd7] #

Nikola Predrag
Nikola Predrag
April 12, 2013 11:12

These 4 solutions are pretty well. It is funny that the added conditions in b) give only one solution.
As soon as I went in bed last night, I “saw” how to avoid 0-position for orthodox promotions. I could not see it looking at the chessboard:
W: Ka8,Pe7;B: Kc8;nPg7;b)Kc8->f7;c)Ka8->h7

Janos Mikitovics
Janos Mikitovics
April 12, 2013 20:17
Reply to  Nikola Predrag

Congratulations, Nikola!

Nikola Predrag
Nikola Predrag
April 18, 2013 10:19

Oh, thanx Janos. I didn’t read your words, I thought it was an older post.
The last position is perhaps interesting because all white moves are the promotions – double AUW by White in matching pairs.