Julia's Fairies

No.606 (JV)

Julia Vysotska


Original Problems, Julia’s Fairies – 2014 (III): September – December

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No.606 by Julia Vysotska – Chameleons with Back-to-Back condition! (JV)


Back-To-Back: When pieces of opposite colors stand back-to-back with each other on the same file (white piece is on the top of black!), they exchange their roles. A pawn on the first rank cannot move. Any piece can make an en passant capture when it has got a role of Pawn by Back-To-Back.

Chameleon: On completing a move, a Chameleon (from classical standard type) changes into another piece, in the sequence Q-S-B-R-Q… Promotion may be to a chameleon at any stage in the cycle.

No.606 Julia Vysotska

original – 23.09.2014

Solutions: (click to show/hide)

White Kc2 Be7 Pd6 Pg3 Black Ke8 Pc4 Ph3 White Chameleon Qg2 Black Chameleon Qf7 Bd7

h#2             2 solutions           (5+5)
Chameleons: Qg2, Qf7, Bd7

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September 25, 2014 10:41

What is interesting is the avoided mate in the first solution 2.cSc6? 3.cQc5! Wish there was a similar effect in the other solution!

Nikola Predrag
Nikola Predrag
September 25, 2014 12:39
Reply to  seetharaman

Yes, this virtual play makes the dynamics of the problem. It would be worth to make the virtual play clear and convincing and use it as the main motivation for the real play.

The virtual content is present here but it’s not in a clear balance with the other solution.
1.cQd5/f5=cS? cQe4=cS 2.cSe3=cB cQg6=cB+ 3.cBg5=cR!

Nikola Predrag
Nikola Predrag
September 25, 2014 13:25
Reply to  Nikola Predrag

Correction of my previous post:
2…cSg6=cB+(not cQg6)

Julia has actually mentioned indirectly the virtual play:
“Position of the pairs wcSd5+bcQd4 and wcSe2+bcBe1 is determined by pawns c4/g3 preventing BTB specific defenses 3.cQd4-a4=cS / 3.cBe1-h4=cR.”

wcSe2+bcBe1 is determined because that pair as wcSe4+bcBe3 wouldn’t work due to the thematic defense 3.cBg5!
I don’t see the other potential position of the pair wcS+bcQ where the same defense would appear.

So, bPc4 does not determine the play of that pair but only the mating move 2…cSb5=cB#!(2…cSc6=cB+?).
wPg3 determines the complete play of the pair wcQg2+bcQf7.
Thus the logic behind wPg3 is much more dynamical and deeper, therefore wPg3 appears as an element which is “active” during that whole phase.
bPc4 is static/irrelevant until the very end and appears as a mere dual-stopper.

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