skb-photoS. K. Balasubramanian 
(India)  &

ptrittenPierre Tritten


Original Problems, Julia’s Fairies – 2014 (III): September – December

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No.611 by S. K. Balasubramanian & Pierre Tritten – A pawn is accompanied by one of the black S/B on its trip till mate! (JV)


Back-To-Back: When pieces of opposite colors stand back-to-back with each other on the same file (white piece is on the top of black!), they exchange their roles. A pawn on the first rank cannot move. Any piece can make an en passant capture when it has got a role of Pawn by Back-To-Back.

No.611 S. K. Balasubramanian & Pierre Tritten
India / France

original – 28.09.2014

Solutions: (click to show/hide)

White ke8 se4 pd4 pe2 Black ke6 bf2 bf5 sc2 pc4 pf4

h#2             2 solutions          (4+6)

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Sebastien Luce
Sebastien Luce
5 years ago

One original idea with good unity between the two variations, like allways with the two authors.

Kjell Widlert
Kjell Widlert
5 years ago

Interesting that Back-To-Back seems to have caught on, whereas last year’s Face-To-Face (which is exactly the same, only rotated 180 degrees) appears to be forgotten! The difference, probably, is just that BTB was implemented in Popeye before the Sake tourney in Bern, while FTF was implemented only after the Sake tourney in Batumi…

shankar ram
shankar ram
5 years ago

Nice echoing of effects by B and S..
Is it worth saving a BP by removing BPc4..
and having a twin b) BPf4-c4?
Winchloe says OK..

S. K. Balasubramanian
S. K. Balasubramanian
5 years ago

Dear Shnkar Ram,

We already noticed that the problem can be made with a twin by reducing one of the black pawns (c4 or f4). But we preferred the 2 solutions form.


5 years ago

Twinning is preferable if it is sbutle enough to make one wonder why the other solution will not work. 🙂