Stephen Emmerson (England)


Original Problems, Julia’s Fairies – 2015 (I): January – June

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No.729 by Stephen Emmerson – 100$ theme with Slow excelsiors. (JV)


Reverse Pawn (PP): Moves opposite to normal Pawn and promotes at the opposite end of board.

Antelope: (3,4) Leaper.

KoKo: A move is possible only if the piece moved arrives on a square next to another unit.

No.729 Stephen Emmerson

original – 19.02.2015

Solution: (click to show/hide)

white  ka7 anc4 ph2 black kf7 ppg2

h#6                                            (3+2)
Reverse pawn g2
Antelope c4

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February 19, 2015 14:25

Nice! Interesting use of the WK !

Kjell Widlert
Kjell Widlert
February 19, 2015 17:16

Clever idea to use one reversible pawn in combination with Köko to motivate the slow Excelsiors! Also a very good, Köko-specific way to determine the black promotion: 6.g8R? 7.Ra8,b8! or 6.g8B? 7.Bh7!

The Antelope is not involved in the thematical play, but seems to be the best (or the only reasonable?) way to guard f8 and g7.

Stephen Emmerson
Stephen Emmerson
February 19, 2015 23:05
Reply to  Kjell Widlert

Couldn’t avoid the antelope… wSe6 creates need for even more guards after which cooks arise quickly; moving one file to the left means bS can escape to h7, and if bP plugs h7 it can escape to g6. Royal Fers f7 instead gives cooks after 1…h4 (N.B. this is a try in the above). And even a Zd5 won’t do.

Stephen Emmerson
Stephen Emmerson
August 2, 2017 16:58

I have just discovered a twin for this position: (b) AN->c2, solving by 1.PPg3 h4…5.PPg7 h8Q 6.Kg6 Qh5. Both this and the (a) mate are models, but this part should remain a footnote mainly because the first five black moves are the same.

August 3, 2017 09:10

This can be a legitimate twin if black pawn also promoted, even if initial moves same.