Fairy chess composition

# No.930,931 (PR)

 No.930, 931 Paul Rãican(Romania) Original ProblemsJF Retro and PG problems 2015-2016    →Previous ; →Next ; →List 2015(II) Please send your original fairy problems to: julia@juliasfairies.com

No.930, 931 by Paul Rãican – PG problems featuring two different fairy conditions. (JV)

No.931.1 by Paul Rãican – Correction to No.931 after comment by Gregor Werner. (JV)

No.930.1 by Paul Rãican – Correction to No.930 after comment by Georgy Evseev. (JV)

Definitions:

Sentinels: When a piece (Ks included but not pawns) moves, a pawn of the same colour appears on the vacated square unless that square is on the first or eighth ranks or there are 8 pawns of that colour on the board already.

Annan Chess: If two pieces of the same colour are standing close to each other in N-S-direction, the front piece moves only like the rear piece as long as the contact is existing. The front piece is that piece that is closer to the own promotion line. White/Black Pawns on the 1st/8th rank cannot move, but can give their kind of moving to a front piece. Officers moving with the power of a Pawn to the promotion line do not promote; if they make a double-step with the power of a Pawn, they cannot be captured en-passant; but officers with the power of a Pawn can capture a Pawn en-passant.

 No.930 Paul RãicanRomaniaoriginal – 14.10.2015 Solution: (click to show/hide) white Bf1c1 Ke1 Qd1 Ph2g2f2e2d2c2b2a2 Sg1b1 Rh1a1 black Bf8c8 Ke8 Qd8 Ph7g7f7e7d7c7b7a7 Sg8b8 Rh8a8 PG 11                            (12+14)    C-Sentinels 1.Sg1-h3 d7-d5 2.Rh1-g1 Bc8*h3 3.g2*h3 g7-g5 4.Rg1*g5 Bf8-g7 { } 5.Rg5*d5 Bg7*b2[+bPg7] 6.Sb1-a3 Bb2*a3[+bPb2] 7.Ra1-b1 b2*c1=S { } 8.Rb1-b3 Sc1*e2 9.Qd1*e2 Ba3-d6[+bPa3] 10.Qe2*e7[+wPe2] + Bd6*e7[+bPd6] { } 11.Rb3*a3[+wPb3] Be7-f8[+bPe7] {dia (C-)} S-Ceriani-Frolkin, bB-circuit. (Author) No.930.1 Paul RãicanRomaniaversion of No.930 – 09.11.2015 Solution: (click to show/hide) white Bf1c1 Ke1 Qd1 Ph2g2f2e2d2c2b2a2 Sg1b1 Rh1a1 black Bf8c8 Ke8 Qd8 Ph7g7f7e7d7c7b7a7 Sg8b8 Rh8a8 PG 11.5                         (11+14)    C-Sentinels 1.Sg1-h3 d7-d6 2.Rh1-g1 Bc8*h3 3.g2*h3 g7-g6 4.Rg1*g6 Bf8-g7 { } 5.Rg6*d6 Bg7*b2[+bPg7] 6.Sb1-a3 Bb2*a3[+bPb2] { } 7.Ra1-b1 b2*c1=S 8.Rb1-b2 Sc1*e2 9.Qd1*e2 Ba3*d6[+bPa3] { } 10.Qe2*e7[+wPe2]+ Bd6*e7[+bPd6] 11.Rb2*b7[+wPb2] { } Be7-f8[+bPe7] 12.b2*a3 {dia (C-)} S-Ceriani-Frolkin, bB-circuit. (Author) No.931 Paul RãicanRomaniaoriginal – 14.10.2015 Solution: (click to show/hide) white Bf1c1 Ke1 Qd1 Ph2g2f2e2d2c2b2a2 Sg1b1 Rh1a1 black Bf8c8 Ke8 Qd8 Ph7g7f7e7d7c7b7a7 Sg8b8 Rh8a8 PG 13                            (13+12)    C-Annan Chess 1.c2*h7{display-departure-square} f7-g6{display-departure-square} 2.d2-d6{display-departure-square} Ke8-f7 3.Qd1-d5+ Kf7*d5{display-departure-square} 4.Sb1-c3+ Kd5-c6 { } 5.Sc3-d5 Qd8-e8 6.d6*c8=Q!{display-departure-square} e7-d6{display-departure-square} 7.Qc8*b8 Qe8*e2+ 8.Sg1*e2 Bf8-e7 { } 9.Qb8-f8 Ra8-e8 10.Qf8-f3 Be7*e2{display-departure-square} 11.f2-e3{display-departure-square} Be2-a6 12.Qf3-d1 b7-b5 13.Ke1-e2 Ba6-c8 {dia (C-)} Q Phoenix-Pronkin, impostor Bc8. (Author) No.931.1 Paul RãicanRomaniaversion of No.931 – 08.11.2015 Solution: (click to show/hide) white Bf1c1 Ke1 Qd1 Ph2g2f2e2d2c2b2a2 Sg1b1 Rh1a1 black Bf8c8 Ke8 Qd8 Ph7g7f7e7d7c7b7a7 Sg8b8 Rh8a8 PG 11                            (15+12)    C-Annan Chess 1.c2*h7{display-departure-square} f7-g6{display-departure-square} 2.d2-d6{display-departure-square} Ke8-f7 3.Qd1-b3+ Kf7*b3{display-departure-square} 4.Sb1-c3 g7-e6{display-departure-square} { } 5.Sc3-d5 Bf8-g7 6.d6*c8=Q!{display-departure-square} g6-b1=B{display-departure-square} 7.Qc8*b8 Bb1-d3 8.Qb8*a7 Bd3-c4 { } 9.Qa7-d4 Ra8-a3 10.Sd5-a5+{display-departure-square} Kb3-a4 11.Qd4-d1+ Bc4-b3 {dia (C-)} Q Phoenix-Pronkin. (Author)

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Gregor Werner
November 5, 2015 18:40

On proof games with the condition Annan chess, a small curse seems to lie:

1. c2xh7 f7-g6 2. Sg1-f3 d7-d6 3. Sf3-f4 Sb8-d7 4. Sf4-e6 b7-b5 5. Se6xf8 Lc8-b7 6. Sf8xd7 Ke8xd7 7. Sb1-c3 Dd8-e8 8. Sc3-d5 Kd7-c6 9. e2-e3 d7-e7 10. e3-e4 De8xe4+ 11. d2-e2 De4xe2+ 12. Ke1xe2 Ta8-e8+ 13 f2-e3 Lb7-c8

Paul Rãican
November 6, 2015 11:30

Thank you, Gregor. By the way, just seen that last move in intention is illegal (a blindness).

seetharaman
November 6, 2015 18:20

930…. Nice that it shows a theme impossible in orthodox chess – Circuit of BB still hemmed by pawns!

Georgy Evseev
November 7, 2015 11:12

930 is also cooked.

1.Sh3 d5 2.Rg1 Bxh3 3.gxh3 Qd6 4.Rg5 Qa3 5.Rxd5 Qxa2(+a3) 6.b3 Qxc2 7.Ra2 Qxc1 8.Sxa3 Qxa3 9.Qc2 Qd6(+a3) 10.Qxc7(+c2) Qxc7(+d6) 11.Rxa3(+a2) Qd8(+c7)

seetharaman
November 7, 2015 16:19

Great findings Georgy Evseev. Again proving your known prowess in solving !

Georgy Evseev
November 10, 2015 13:46

930.1 seems still cooked.

Cook built without board, I’ll check it in the evening.

1. Sh3 d6 2.Rg1 Bh3 3.gxh3 Qd7 4.Rg6 Qxb2 5.Sc3 Qxc3 6.Ba3 Qxc2 7.Bxd6(+a3) Qxg6(+c2) 8.Rb1 Qxd6 9.Qxc2 Qd8(+d6) 10.Qxc7(+c2) Qxc7 11.Rb2 Qd8(+c7) 12.Rxb7

Georgy Evseev
November 10, 2015 18:40

Well, it is not working)))

Kenneth Solja
November 10, 2015 18:48

Georgy, there is a misprint or something
1. Sh3 d6 2.Rg1 Bh3 3.gxh3 Qd7 4.Rg6 Qxb2 5.Sc3 Qxc3 6.Ba3 Qxc2 7.Bxd6(+a3) Qxg6(+c2) 8.Rb1 Qxd6 9.Qxc2 Qd8(+d6) 10.Qxc7(+c2) Qxc7 11.Rb2 Qd8(+c7) 12.Rxb7, because bQ can’t go from d7 to b2 in one move.

Paul Rãican
November 22, 2015 09:59

It is an attempt for 930.1: 1.Nb1-a3 Pb7-b5 2.Ng1-h3 Pb5-b4 3.Rh1-g1 Pb4xa3 4.Pb2xa3 Nb8-c6 5.Bc1-b2 Pd7-d6 6.Bb2-e5 Bc8xh3 7.Pg2xh3 Nc6xe5(+pc6) 8.Rg1-g4 Ne5xg4 9.Qd1-b1 Ng4-e5
10.Qb1-b8 Ne5-d7 11. Ra1-b1 Nd7xb8 12. Rb1-b7, but we have an unwanted Pawn c6.

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