OganesjanNo.962 
Aleksey Oganesjan
(Russia)
JF-LOGO-1

Original Problems, Julia’s Fairies – 2015 (II): July – December

   →Previous ; →Next→List 2015(II)

Please send your original fairy problems to: julia@juliasfairies.com


No.962 by Aleksey Oganesjan – Underpromotions and bicolor Bristol in HS# Meredith without fairy pieces. (JV)

No.962.1 by Aleksey Oganesjan – An improved version of No.962, after comment by N.Predrag. (JV)


No.962 Aleksey Oganesjan
Russia

original – 27.11.2015

Solutions: (click to show/hide)
White Kg8 Qa2 Rh5 Ra1 Bg1 Ph7 Pa4 Black Ka5 Be5 Pa7 Pa6 Pb2

hs#3,5               zero                (7+5) a) Bg1→g7; b) Kg8→g2


No.962.1 Aleksey Oganesjan
Russia

version of No.962 – 03.12.2015
Dedicated to Nikola Predrag

Solutions: (click to show/hide)
White Kg2 Qa2 Rh5 Ph7 Pg6 Pa3 Black Ka5 Be5 Pa7 Pg7 Pa6 Pa4 Pd2

hs#3,5               zero                (6+7)
a) Kg2→g8; b) Pg7→h2


Subscribe
Notify of
guest
7 Comments
Oldest
Newest Most Voted
Inline Feedbacks
View all comments
seetharaman
seetharaman
November 30, 2015 21:57

Very nice! Is it better to have the black pawn b2 at d2?

Aleksey Oganesjan
Aleksey Oganesjan
December 1, 2015 08:32

No, it’s not better, because if bPb2->d2 then cooks in a) will appear:
1…Kb4/Kb6 2.a5 Kb5 3.Bf8 d1Q 4.Qd5+ Qxd5#
(and three more cooks, with another order of moves)

Nikola Predrag
Nikola Predrag
December 1, 2015 16:55

bPd2 would be better because in a), 3….Rd8-a8 would be a critical Bristol-move across b8. Rb8-a8 is not a Bristol-move.

And wB has a function of a Dummy which is too expensive for a helpselfmate. bP g7/h2 would be much cheaper than wB g7/g1.

Also, wRa1 is only a static guard of a4 which could be blocked by bP which could be immobilized by wPa3.

seetharaman
seetharaman
December 1, 2015 23:12
Reply to  Nikola Predrag

hm…. bph2/g7 is an obvious choice, but how to stop h2 pawn for the ZZ finale?

seetharaman
seetharaman
December 1, 2015 19:24

You are right of course. I tested with expensive BSa4!

Aleksey Oganesjan
Aleksey Oganesjan
December 1, 2015 19:55
Reply to  seetharaman

Yes, you are right – the version with bSa4 and bPb2->d2 is correct, and I saw it during composing… But in this case the mates are not model (in view of this bSa4). Also, according a principle of economy, I prefer the published version with wPa4.

Nikola Predrag
Nikola Predrag
December 2, 2015 00:17

Zero-position, just as the original:
White Ph7 Pg6 Rh5 Pa3 Qa2 Kg2
Black Pa7 Pg7 Pa6 Ka5 Be5 Pa4 Pd2
Hs#3.5; Zero Move g2 g8; Twin Move g7 h2