No.376 Petko A. Petkov (Bulgaria)

Original Problems, Julia’s Fairies – 2013 (III): September- December   →Previous ; →Next ; →List 2013(III) Please send your original fairy problems to: julia@juliasfairies.com

---

No.375 by Petko A. Petkov  – My lovely “horses” actively play in this wonderful birthday gift! Complicated strategy in creation of direct and indirect anti-batteries.
I’m very touched and grateful to Petko! (JV)

---

Definitions:

Grasshopper(G): Moves along Q-lines over another unit of either color to the square immediately beyond that unit. A capture may be made on arrival, but the hurdle is not affected.

Nightrider(N): A Rider along a straight line on squares lying a Knight`s move away from each other.

PAO(PA): Moves as Rook, but captures only by hopping over a hurdle to any square beyond.

Take & Make: Having captured, a unit must immediately, as part of its move, play a non-capturing move in imitation of the captured unit from the capture-square. If no such move is available, the capture is illegal. Promotion by capture occurs only when a pawn arrives on the promotion rank as the result of a take&make move. Checks are as in normal chess: after the notional capture of the checked K, the checking unit does not move away from the K’s square.

---

No.376 Petko A. Petkov Bulgaria original-16.09.2013 Dedicated to Julia Vysotska at her birthday 16.09.2013!   hs#2,5           2 solutions             (8+5) Take & Make Nightriders: d3, e7, h6 Grasshoppers: d6, e6 PAOs: a1, b1, h5     Solutions: (click to show/hide)   I. 1…Nd4 2.Gxd4(Gb3) Nh1 3.Nxh1(Nf5)+ Kxe6(Ka2)‡ II. 1…Nc6 2.Gxc6(Gb4) Nf7 3.Nxf7(Ng5)+ Kxd6(Ka3)‡ (C+ by Popeye 4.63 and WinChloe 3.24)   Creation of black anti-batteries K/PAO after passive sacrifices to the w.G. Four sacrifices by the black Ns with the goal: attraction of the white Grasshoppers on b3/b4 and of the white N on f5/g5 that creates anti-batteries with the w.PAO. Creation of indirect anti-batteries w.G/black PAO. Interchange of functions between Gd6/Ge6 and Ne7/Nh6. Model mates. The main idea in this problem is super-activity of the three Nightriders and of course – the difficulty of solutions. (Author)

---

No.356  Dominique Forlot (France)

Original Problems, Julia’s Fairies – 2013 (II): May – August  →Previous ; →Next ; →List 2013(II) Please send your original fairy problems to: julia@juliasfairies.com

---

No.356 by Dominique Forlot  – A nice Masand-Miniature with AUW! (JV)

---

Masand: A unit which moves and actively checks changes the colour of all the units – enemy and its own (not Ks) – which it observes after the move. A checking rear (non-moving) piece of a battery would not recolour the units it observes.

---

No.356 Dominique Forlot France original-10.08.2013   h#2                2 solutions             (4+3) Masand   Solutions: (click to show/hide)   I. 1.d2-d1=B g7-g8=Q 2.Bd1-b3 Qg8-e6[e2=b][b3=w][d7=w] # II. 1.Ke7-e8 g7-g8=S 2.d2-d1=R[d7=w] + Be2-h5[d1=w] # (C+ by Popeye 4.63)   A Miniature illustrating the condition Masand. (GMI Petko Petkov , feenschach, 2001). Both solutions, easy to solve, show an AUW without capture. (Author).

---

No.354 Petko A. Petkov (Bulgaria)

Original Problems, Julia’s Fairies – 2013 (II): May – August  →Previous ; →Next ; →List 2013(II) Please send your original fairy problems to: julia@juliasfairies.com

---

No.354 – Petko A. Petkov – Wonderful Disparate problem! Enjoy author’s detailed comments to all 3 solutions! I’m so grateful for the dedication! (JV)

---

Definitions:

Camel – (1,3) Leaper

Zebre – (2,3) Leaper

Disparate: If one side makes a move with a piece of type “x” (black, white, neutral, half-neutral, etc., King included), the other side cannot answer immediately by moving a piece of the same type “x”. (For example: white Qc1, black Ka8,Qa7 – mate in 1 move. After 1.Qc8#, Black is mated because 1…Qb8? is illegal. The mate is possible also with the neutral nQc1 – after 1.nQc8#. Black cannot move the same neutral Queen.) Every Pawn’s promotion is a Pawn’s move, therefore after such promotion (into any possible piece) the other side cannot answer immediately with its Pawn. We can say that after the move of the figure of type “x” any enemy figure of type “x” falls under Half-moving paralysis. This paralysis disappears immediately on the next half-move, if the opponent plays with another piece of type “y”.
This is the main version of Disparate (the programmer is Stephen Emmerson), that is presented only in Popeye (starting 4,53 version), and answers to the definition of the inventor Romeo Bedoni (2004) and to the requirements about this condition of the editors of “Phenix”. Using Popeye‘s version of Disparate in 2010 was organized a big international tournament Bedoni – 80 Jubilee, with results published in the magazine “Phenix” – No.191-192/2010. In the same number was also published a big article by Petko A.Petkov about Disparate, dedicated to its inventor Romeo Bedoni.  Important note: Disparate condition is not included in Popeye‘s manual, but it is implemented there and can be used as “Disparate“.
Another version of Disparate you can find in WinChloe, but it is based on the different rules.  

---

No.354 Petko A. Petkov Bulgaria original-02.08.2013 Dedicated to Julia Vysotska!                                  hs=3                                   (1+7+7)      (С+ Popeye 4.63) b) Pb4→b6 c) Pe3→c6 DISPARATE Camels: c1, g7  Zebras: f1, f8     Solutions: (click to show/hide)   a) 1.nQxg7 (A) nBc3! 2.nQxf6 (B) nZxc3!! 3.nQa6 +!! nZxa6 =!! –AB white moves, nZx nB captures by black afer nBe1 sacrifice on c3 ! In the final position: nZf8 and nZa6 are paralysed for White, nCAc1 is pinned! Pay attention that after 3.nQa6+! the nQ is paralyzed for black, but paralyzed is also Qb2 and the defenses 3…Qa2?? or 3…Qa3?? are illegal! A lot of thematical tries and dual-avoidance motives with Disparate motivation are possible here: At first: 1.nBc3? – if here 1….nZxc3? 2.nQxg7? the nQ is paralyzed for Black and it is impossible 2…nQxf6?? After 1…nQxg7? White cannot play 2.nQxf6?? but after 2.nZxc3? nQxf6?? the nQ is paralyzed for White and the move 3.nQa6+? is impossible! The anti-dual effect is also demonstrated after 1.nQxg7 and here black cannot play 1…nQxf6? because the nQ is paralyzed for Black! b) 1.nQxf6 (B) nZd4! 2.nQxf8 (C) nCAxd4!! 3.nQa3 +!! nCAxa3 =!! – BC white moves, nCAx nZ captures by black afer nZf1 sacrifice on d4! In the final position: nCAg7 and nCAa3 are paralyzed for White, nBe1 is pinned! Thematical tries and dual-avoidance motives with Disparate motivation are: At first: 1.nZd4? – if here 1….nCAxd4? 2.nQxf6? the nQ is paralized for Black and it is impossible 2…nQxf8??. After 1…nQxf6? White cannot play 2.nQxf8?? but after 2.nCAxd4? nQxf8?? the nQ is paralyzed for White and the move 3.nQa3+? is impossible! The anti-dual effect is also demonstrated after 1.nQxf6 and here black cannot play 1…nQxf8? because the nQ is paralyzed for Black! c) 1.nQxf8 (C) nCAf2! 2.nQxg7 (A) nBxf2!! 3.nQa7+!! nBxa7 =!! – CA white moves, nBxnCA captures by black after nCAc1 sacrifice on f2! In the final position: nBa7 and nBf6 are paralyzed for White, nZf1 is pinned! Thematical tries and dual-avoidance motives with Disparate – motivation are: At first: 1.nCAf2?– if here 1….nBxf2? 2.nQxf8? the nQ is paralyzed for Black and it is impossible 2…nQxg7??. After 1…nQxf8? White cannot play 2.nQxg7?? but after 2.nBxf2? nQxg7?? the nQ is paralyzed for White and the move 3.nQa7+? is impossible! The anti-dual effect is also demonstrated after 1.nQxf8 and here black cannot play 1…nQxg7? because the nQ is paralyzed for Black! THEMATICAL COMPLEX: Play of two trios of neutral pieces: FIRST TRIO: nCAc7, nBf6, nZf8 – in this trio we see a cyclical Passive Annihilation-captures AB – BC – CA, realized by the neutral Queen. SECOND TRIO: nCAc1, nBe1, nZf1 – in this trio we see a cyclical Active Annihilation-captures nBc3>nZxc3, nZd4>nCAxd4, nCAf2>nBxf2. This cycle is combined with a third-pin on the 1st line! A lot of half-moving paralysis (for Black and for the White) are demonstrated from the neutral Queen. These typical Disparate effects motivate tries and dual-avoidance moves in the different phases of both solutions. (Author)

---

My debut in WCCI 2010-2012

It was my first participation in WCCI, and of course, I’m happy, and excited, and very interested in all results…. Everyone can imagine!

I’ve participated in Fairy section (judges according to order of their scores: Juraj Lörinc, Franz Pachl, Petko Petkov, Tadashi Wakashima, Klaus Wenda), the place No.21 (considered a lucky number!) in the list of results, 29.50 points in total, with the following problems:

• No.1 (2; 2.5; 3; 2; 2 -> 6.50)  – JV-34:

---

Julia Vysotska KoBulChess TT 2012, AWARD-April-2012 2nd Prize hs#3         2 solutions       5+5 KoBul Kings  Grasshopper d3  Leo c1

Solutions: (I) 1.Qd4 cxd4 [wrK=rQ] 2.rQd1 LEd2 3.Gd5 + LExd5 [wrQ=rG] # – not 4.rGxd5(bK= brLE)?? – self-check!! (II)1.Qb3 cxb3 [wrK=rQ] 2.rQg3 LEe3 3.Ga3 + LExa3 [wrQ=rG] # – not 4.rGxa3(bK= brLE)?? – self-check!! Realization of the KoBul Kings fairy condition with activity of the both KoBul Kings: – Active phase of the white KoBul King after sacrifice of the white Q -transformation to the Royal Q, which moves to the mating positions. – Passive phase of the white Kobul King on the mating move – transformation to the Royal G, which has no possible moves to avoid the mate. – Passive phase of the black KoBul King –  the only possible defense of the white King  (in the Royal G phase) – capture of the mating piece (bLE) – falls because it transforms the black King into Royal LE piece giving the self-check. Double Ambush – black (Le) + white (rQ); Bristol theme – wG opens lines for the second moves of bLE; ODT; Model mates.

---

• No.2 (3; 3; 3; 2; 2.5 -> 8.50) – SELECTED FOR FIDE ALBUM 2010-2012 – JV-61:

---

Julia Vysotska Chameleon-50JT 2012 , KobulChess.com 1st Prize hs#3,5      b) Sd4->e5     (7+6) Chameleons: Qa1, Bh8

Solutions: a) 1…Sd4-e2 2.e7-e8=cQ cQa1-f6=cS + 3.Ke4-e5 + Kb7-b8 4.cQe8-d7=cS + cSf6*d7=cB # (try: 1…Sd4-e6? 2.e7-e8=cQ cQa1-f6=cS + 3.Ke4-e5 + Kb7-b8 4.cQe8-d7=cS + cSf6*d7=cB – no mate, 5.Kf5!) b) 1…Se5-g4 2.e7-e8=Q cBh8-b2=cR 3.Ke4-d4 + Kb7-a6 4.Qe8-b5 + cRb2*b5=cQ # (try: 1…Se5-c4? 2.e7-e8=Q cBh8-b2=cR 3.Ke4-d4 + Kb7-a6 4.Qe8-b5 + cRb2*b5=cQ – no mate, 5.Kd3!)   Creation of black reciprocal batteries CS/CB & CR/CQ after critical moves of black Chameleons. Interchange of functions between the both black Chameleons. Thematic tries of black S with Bivalve-theme. Play of two King’s batteries K/B from both sides. White promotions in Q and CQ.

---

• No.3 (2; 3.5; 3; 2; 2 -> 7.00) – JV-25:

---

Julia Vysotska Best Problems – 2012, No.63 (Jul 3/2012), #2927 hs#3     b) pc4->d3        7+10 Andernach Chess PAOs: a5, h8, a1 Nightrider c8 VAO h1

Solutions: a) 1.PAa5-a6 Nc8-e4 2.Rf3-f5 Ne4*a6=wN + 3.Rf5-d5 + Bg8*d5=wB # b) 1.PAa5-a2 Bg8-d5 2.Rf3-e3 Bd5*a2=wB + 3.Re3-e4 + Nc8*e4=wN # Sacrifices of white PAO (on a2/a6) with the goal: Annihilation + change of color of the black B and N. Unpins of white Rf3 with Ne4/Bd5; black half-battery play N-B/PAO; creation of black batteries N/VAO and B/VAO. Model mates after three white pins (2 active and one passive).

---

• No.4 (2; 2.5; 2.5; 1; 1.5 -> 6.00) – JV-17:

---

Julia Vysotska Orbit – 2012, No 54 (May-2012), F38 h#2        b) Sb3->f4       1+7+4 Grasshoppers: f2, d1; Lions: d8, a7

Solutions: a) 1.Sc1 nGb1 2.Sd3 nGb6# (3.nGd6? 3.nGe3? 3.nLic5? or not also 3.Gb4?) b) 1.Sg2 nGh2 2.Se3 nGd6# (3.nGb6? 3.nGd3? 3.nLid5? or not also 3.Gf4?) Creation of neutral anti-batteries (nG/nLi) with 3 tries of a neutral Gs on the mating move in each solution, which gives a self-check, creating a specific anti-batteries. Opening of line (for the nGs) and self-blocks on the black’s second moves.

---

• No.5 (1.5; 3; 3; 2.5; 2 -> 7.50)  – JV-30:

---

Julia Vysotska The Problemist – 2012, Vol.23 No.11 (Sep-2012), F2990 h#2,5*                         5+5+3 Moa d6; Mao e4 Locusts: a6,b1

Solutions: Set-play: 1.Qf4 nMO×e4+ 2.Kf5 nMOg3‡ 1…Ka4 2.Qe7 nMA×d6+ 3.Kf6 nMAe8‡ Block of the neutral Locust by the white King; Zilahi theme; Reciprocal transformation of neutral batteries: Initial battery MOA/LO to MAO/LO and initial battery MAO/LO to MOA/LO after reciprocal captures of their forward-pieces. Bi-valve realized by the black Q: line opening for the neutral Mao/Moa, line closing for the neutral Moa/Mao on the mating move. Distant self-block by the black Q. Pins of black Q by the neutral Mao/Moa.

---

• No.6 (1.5; 3.5; 3; 1.5; 1.5 -> 6.00) – JV-32:

---

Julia Vysotska Tehtäväniekka – 2012, No.2/2012, #3844 h#2,5      2 solutions    2+7+5 Mao b7; Moa b3 Vao b6; Pao a4

Solutions: (I) 1…nRg1 2.Sa8 nRa1 3.S×b6 nPA×a1‡ (II) 1…nRg8 2.Sc3 nRd8 3.S×a4 nVA×d8‡ Zilahi;  selfblocks with simultaneous selfpins of black Sa2/Sc7; change of functions of Sa2 and Sc7; neutral battery VA-MA / PA-MO play with sacrifice of neutral R for VA/PA move;  change of functions of nMOA-b3 and nMAO-b7.

---

Problems were ordered by my understanding which one is better, the judges views were a bit different. But I’m very happy that No.2 –  with my favorite Chameleon piece(!) – goes to FIDE Album!

---